我是CodeIgniter的初学者,我正在关注官方网站上的教程。我完成了静态页面。当尝试新闻示例并打开链接index.php/news
时,它显示未找到消息404。
应用/控制器/ News.php
<?php
class News extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->model('news_model');
$this->load->helper('url_helper');
}
public function index()
{
$data['news'] = $this->news_model->get_news();
$data['title'] = 'News archive';
$this->load->view('templates/header', $data);
$this->load->view('news/index', $data);
$this->load->view('templates/footer');
}
public function view($slug = NULL)
{
$data['news_item'] = $this->news_model->get_news($slug);
if (empty($data['news_item']))
{
show_404();
}
$data['title'] = $data['news_item']['title'];
$this->load->view('templates/header', $data);
$this->load->view('news/view', $data);
$this->load->view('templates/footer');
}
}
应用/视图/消息/ index.php的
<h2><?php echo $title; ?></h2>
<?php foreach ($news as $news_item): ?>
<h3><?php echo $news_item['title']; ?></h3>
<div class="main">
<?php echo $news_item['text']; ?>
</div>
<p><a href="<?php echo site_url('news/'.$news_item['slug']); ?>">View article</a></p>
<?php endforeach; ?>
应用/视图/消息/ view.php
<?php
echo '<h2>'.$news_item['title'].'</h2>';
echo $news_item['text'];
应用/配置/ routes.php文件
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
$route['news/(:any)'] = 'news/view/$1';
$route['news'] = 'news';
$route['(:any)'] = 'pages/view/$1';
$route['default_controller'] = 'pages/view';
答案 0 :(得分:0)
更改此行
$route['news'] = 'news';
要
$route['news'] = 'news/index';
答案 1 :(得分:0)
这应该是
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
此
if (!defined('BASEPATH'))
exit('No direct script access allowed');
并将其放在.htaccess
(外部应用程序文件夹)
<IfModule mod_rewrite.c>
RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^(.*)$ index.php/$1 [L]
</IfModule>