Question

请您查看 This Demo ，然后让我知道为什么弹出窗口在按.close按钮关闭后第一次点击无效？

＆＃13;

 $("#pop-One").popover({
        placement: 'right',
        html: 'true',
        title : '<span class="text-info" style=""><strong>Model Type</strong></span>'+
                '<button type="button"  class="btn btn-default close" onclick="$("#pop-One").popover("hide");">×</button>',
        content : '<p class="popup" style="color:#323232;"> \Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry standard dummy text ever since the 1500s,</p>'
    });

＆＃13;

@import 'https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css';
@import 'https://maxcdn.bootstrapcdn.com/font-awesome/4.4.0/css/font-awesome.min.css';
body{padding:20px;}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
<div class="container">
<button type="button" class="btn btn-default" id="pop-One" data-toggle="popover"><i class="fa fa-question"></i></button>
</div>

＆＃13;

出于什么原因？！关闭按钮在这里不起作用！所以请检查演示页面以查看完整的功能

我已经看过this Post，但这是另一种方法

Answer 1

不知道这是最好的解决方案，但它正在运作

  $("#pop-One").popover({
        placement: 'right',
        html: 'true',
        title : '<span class="text-info" style=""><strong>Model Type</strong></span>'+
                '<button type="button"  class="btn btn-default close"\
     onclick="$(&quot;#pop-One&quot;).popover(&quot;hide&quot;);">×</button>',
        content : '<p class="popup" style="color:#323232;"> \Lorem Ipsum is simply dummy\ text of the printing and typesetting industry. Lorem Ipsum has been the industry standard\ dummy text ever since the 1500s,</p>'
  }).on('shown.bs.popover', function() {
    var popup = $(this);
    $(this).parent().find("div.popover .close").click(function() {
      popup.click();
    });
  });

here the result of my efforts

Answer 2

  <div id="timepickerDue" class="input-group date mytime activitydateblock" uib-popover-template="'myTooltipTemplate.html'" popover-trigger="'outsideClick'" popover-placement="bottom" popover-class="customClass" popover-is-open="isEnable"></div>
 <div uib-popover-template-popup="" uib-title="" content-exp="contentExp()" origin-scope="origScope" class="popover ng-scope ng-isolate-scope bottom customClass fade in" tooltip-animation-class="fade" uib-tooltip-classes="" ng-class="{ in: isOpen }" style="top: 125px; left: 363px;"><div class="arrow"></div>

以上是Popover的HTML标记。

实际问题，为什么它的双击工作，而不是单击是不是很棘手。这背后的原因是bootstrap和angular需要元素点击事件注册。

请使用以下代码在ipod中修复此问题。如果您打算使用非触摸设备，您可以使用$（document）.on（'click'，function（e）而不是$（document）.on（'touchstart'，function（e）

    $(document).on('touchstart', function(e) {
         if ($("div[uib-popover-template-popup='']").hasClass('popover ng-scope ng-isolate-scope bottom customClass fade in') && $(e.target).closest('div[class^="popover-content"]').length <= 0)
         angular.element('#timepickerDue').triggerHandler('click')
  });

关闭它后，Popover不会在首次点击时显示

2 个答案: