Question

我正在尝试使用PHP填充下拉列表，但我继续从选择选项中获取一个空白单元格！任何帮助表示赞赏！

                  <fieldset id="Amount">
              <?php
              include ("connect.php");
              $db = new mysqli($servername, $username, $password, $dbname);
              if(!db) {
                exit('Connect Error (' . mysqli_connect_error() . ') '
                     . mysqli_connect_error());
              }
              ?>
              <label><span class="text_9">AMOUNT:</span></label>
              <select required name="amount" id="amount">
              <option value="">Select</option>
              <?php
              $stmt = $db->prepare("SELECT DISTINCT 'Amount' FROM 'Contracts'");
              $stmt->execute();
              $stmt->bind_result($amt);
              while ($stmt->fetch_()){
                  echo "<option value='$amt'></option>";
              }
              $stmt->close();
              ?>
              </select>
              </fieldset>

谢谢！

Answer 1

尝试类似这样的东西，让html脱离php块

<?php
$stmt = $db->prepare("SELECT DISTINCT 'Amount' FROM 'Contracts'");
$stmt->execute();
$stmt->bind_result($amt);
while ($stmt->fetch_()){
?>


<option value="<?php echo $amt; ?>"> <?php echo $amt; ?> </option>
    <?php
    }
    $stmt->close();
    ?>

Answer 2

从表名中删除单引号并将其更改为：

$stmt = $db->prepare("SELECT DISTINCT 'Amount' FROM Contracts");

并确保您的表格中有数据。

试图用PHP填充下拉列表

2 个答案: