我正试图在。！保留它们，但由于某种原因，它不能正常工作。我做错了什么？
$input = "hi i am1. hi i am2.";
$inputX = preg_split("~[.!?]+\K\b~", $input);
print_r($inputX);
结果：
Array ( [0] => hi i am1. hi i am2. )
预期结果：
Array ( [0] => hi i am1. [1] => hi i am2. )
答案 0 :(得分：2)
我不确定您是否需要执行package com.client.businesstracker.activity;
import android.app.Activity;
import android.app.ProgressDialog;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import com.android.volley.Request.Method;
import com.android.volley.Response;
import com.android.volley.VolleyError;
import com.android.volley.toolbox.StringRequest;
import org.json.JSONException;
import org.json.JSONObject;
import java.util.HashMap;
import java.util.Map;
import com.client.businesstracker.Login;
import com.client.businesstracker.R;
import com.client.businesstracker.loginandregistration.app.AppConfig;
import com.client.businesstracker.loginandregistration.app.AppController;
import com.client.businesstracker.loginandregistration.helper.SQLiteHandler;
import com.client.businesstracker.loginandregistration.helper.SessionManager;
public class LoginActivity extends Activity {
private static final String TAG = RegisterActivity.class.getSimpleName();
private Button btnLogin;
private Button btnLinkToRegister;
private EditText inputServerID;
private EditText inputClientID;
private EditText inputPassword;
private ProgressDialog pDialog;
private SessionManager session;
private SQLiteHandler db;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
inputServerID = (EditText) findViewById(R.id.serverID);
inputClientID = (EditText) findViewById(R.id.clientID);
inputPassword = (EditText) findViewById(R.id.password);
btnLogin = (Button) findViewById(R.id.btnLogin);
btnLinkToRegister = (Button) findViewById(R.id.btnLinkToRegisterScreen);
// Progress dialog
pDialog = new ProgressDialog(this);
pDialog.setCancelable(false);
// SQLite database handler
db = new SQLiteHandler(getApplicationContext());
// Session manager
session = new SessionManager(getApplicationContext());
// Check if user is already logged in or not
if (session.isLoggedIn()) {
// User is already logged in. Take him to main activity
Intent intent = new Intent(LoginActivity.this, Login.class);
startActivity(intent);
finish();
}
// Login button Click Event
btnLogin.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
String serverID = inputServerID.getText().toString().trim();
String clientID = inputClientID.getText().toString().trim();
String password = inputPassword.getText().toString().trim();
// Check for empty data in the form
if (!serverID.isEmpty() && !password.isEmpty() && !clientID.isEmpty()) {
// login user
checkLogin(serverID, clientID,password);
} else {
// Prompt user to enter credentials
Toast.makeText(getApplicationContext(),
"Please enter the credentials!", Toast.LENGTH_LONG)
.show();
}
}
});
// Link to Register Screen
btnLinkToRegister.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
Intent i = new Intent(getApplicationContext(),
RegisterActivity.class);
startActivity(i);
finish();
}
});
}
/**
* function to verify login details in mysql db
* */
private void checkLogin(final String serverID, final String clientID, final String password) {
// Tag used to cancel the request
String tag_string_req = "req_login";
pDialog.setMessage("Logging in ...");
showDialog();
StringRequest strReq = new StringRequest(Method.POST,
AppConfig.URL_LOGIN, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d(TAG, "Login Response: " + response.toString());
hideDialog();
try {
JSONObject jObj = new JSONObject(response);
boolean error = jObj.getBoolean("error");
// Check for error node in json
if (!error) {
// user successfully logged in
// Create login session
session.setLogin(true);
// Now store the user in SQLite
String uid = jObj.getString("uid");
JSONObject user = jObj.getJSONObject("user");
String name = user.getString("name");
String serverID = user.getString("serverID");
String clientID = user.getString("clientID");
// Inserting row in users table
db.addUser(name, serverID, clientID);
// Launch main activity
Intent intent = new Intent(LoginActivity.this, Login.class);
startActivity(intent);
finish();
} else {
// Error in login. Get the error message
String errorMsg = jObj.getString("error_msg");
Toast.makeText(getApplicationContext(),
errorMsg, Toast.LENGTH_LONG).show();
}
} catch (JSONException e) {
// JSON error
e.printStackTrace();
Toast.makeText(getApplicationContext(), "Json error: " + e.getMessage(), Toast.LENGTH_LONG).show();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e(TAG, "Login Error: " + error.getMessage());
Toast.makeText(getApplicationContext(),
error.getMessage(), Toast.LENGTH_LONG).show();
hideDialog();
}
}) {
@Override
protected Map<String, String> getParams() {
// Posting parameters to login url
Map<String, String> params = new HashMap<String, String>();
params.put("serverID", serverID);
params.put("clientID", clientID);
params.put("password", password);
return params;
}
};
// Adding request to request queue
AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
}
private void showDialog() {
if (!pDialog.isShowing())
pDialog.show();
}
private void hideDialog() {
if (pDialog.isShowing())
pDialog.dismiss();
}
但是如果可以选择preg_split()则尝试preg_match_all()：
$input = "hi i am1. hi i am2.";
preg_match_all("/[^\.\?\!]+[\.\!\?]/", $input,$matched);
print_r($matched);
给你：
Array
(
[0] => Array
(
[0] => hi i am1.
[1] => hi i am2.
)
)
答案 1 :(得分：1)
尝试不使用\b，我认为这是多余的（如果不是这种情况）。
$input = "hi i am1. hi i am2.?! hi i am2.?";
$inputX = preg_split("~(?>[.!?]+)\K(?!$)~", $input);
print_r($inputX);
(?!$)是为了避免在匹配的元素上拆分，如果它在字符串的末尾，那么就不会有额外的空结果。原子分组?>是为了避免分裂，如果字符串末尾有一系列字符，如?!.（没有原子分组，它会在!上分割，最后的结果是单个char .）。输出：
Array
(
[0] => hi i am1.
[1] => hi i am2.?!
[2] => hi i am2.?
)
答案 2 :(得分：0)
我希望这是你所期待的
$input = "hi i am1. hi i !am?2."; // i have added other ?! symbols also
$inputX = preg_split("/(\.|\!|\?)/", $input,-1,PREG_SPLIT_DELIM_CAPTURE);
print_r($inputX)
输出：
Array ( [0] => hi i am1 [1] => . [2] => hi i [3] => ! [4] => am [5] => ? [6] => 2 [7] => . [8] => )