Python Count up＆amp;下行循环

Question

如何简单地将此循环转换为从1到100计数，并显示数字？我最近开始编码。倒计时它工作正常，但我无法弄清楚如何从1 -100开始

例如：

query = (from t1 in query
join t2 in RepoTable2.AsQueryable() on t1.Id equals t2.IdTable1 into joint1t2
from t2 in joint1t2.DefaultIfEmpty() // DefaultIfEmpty is used for left joins
join t3 in RepoTable3.AsQueryable() on t2.Id equals t3.IdTable2 into joint2t3
from t3 in joint2t3.DefaultIfEmpty() // DefaultIfEmpty is used for left joins
where t3.Id== null
select t1);

Answer 1

如果使用for循环，它会变得非常简单：

for number in range(1,101):
    print(number)

从100下降到1：

for number in range(100,0,-1):
    print(number)

Answer 2

只需从1开始计数，更改检查语句以检查数字是否小于100，并使用＆＃34; count = count + 1＆＃34;应该工作，祝你好运！

Answer 3

从1开始，并在达到100时将条件更改为中断。每个循环添加1个。

count = 1
while count <= 100:
    print(count)
    count += 1

Answer 4

可以试试'逆转'：

>>> for i in reversed(range(1,11)):
...   print i
... 
10
9
8
7
6
5
4
3
2
1

Answer 5

基本上只是与你已经拥有的相反。

count = 1
while count < 101:
    print(count)
    count = count + 1

Answer 6

试试这个。

count = 0
 while count <= 100:
        print ("Count = ", count)
        count = count + 1