我有一个UNION查询。我试图将2条记录合并为1.上半部分从一组表中获取记录，下半部分从一组不同的表中获取记录。两半都使用来自2个派生查询的字段。结果目前看起来像这样：
Group Branch Ref NUm GL Amt Bank Amt
135 15 1z2x3c 25.00 0.00
135 15 1z2x3c 0.00 25.00
我希望看到的是：
135 15 1z2x3c 25.00 25.00
我在每一半中添加了0.00的字段，因此我有相同数量的列，因为2个半部分带回了不同数量的字段。我还比较了所有字段及其数据类型。如果它们不同，那么我使用CAST来使它们相同。我可以使用UNION执行此操作，还是有其他方法将2行合并为1？我非常感谢你的帮助。感谢.........
这是我开发的sql：
with drvd_qry (operating_unit, grp_brn_id, ecr_dept_id, stn_id) as
(select
soh.operating_unit,
s.grp_brn_id,
s.ecr_dept_id,
s.stn_id
from stns s
inner join rfs.stn_ops_hierarchies soh on soh.stn_stn_id = s.stn_id
where substr(s.grp_brn_id, 1, 2) = 'G1'
group by soh.operating_unit, s.grp_brn_id, s.ecr_dept_id, s.stn_id),
qry_drvd (department, ecr_ticket_no, open_item_id, rnt_agr_nbr, monetary_amount) as
(select
j.department,
j.ecr_ticket_no,
j.open_item_id,
j.rnt_agr_nbr,
cast(j.monetary_amount as decimal (15,2))
from
rfs.journal_entries j
where
j.business_unit = 'A0141'
and j.accounting_date = cast ('23-SEP-2015' as date format 'dd-MMM-YYYY')
and j.account_gl = '109850')
select
bb.BU,
bb.GPBR,
bb.STN_ID,
bb.DEPTID,
cast(ft.mrchnt_nbr as decimal (20,0)) as MERCH_NUM,
bb.TICKET_NUM,
ft.prim_acct_frst_six_dgt_nbr as FIRST6,
ft.prim_acct_last_four_dgt_nbr as LAST4,
bb.AUTH_NUM,
cast(ft.stlmt_uniq_ref_nbr as decimal (20,0)) as REF_NUM,
bb.GL_AMT,
bb.BANK_AMT
from
(select
aa.bu,
aa.gpbr,
aa.stn_id,
aa.deptid,
aa.ticket_num,
p.auth_nbr as AUTH_NUM,
p.fin_tran_ref_id,
aa.GL_AMT,
CAST(0 AS DECIMAL (15,2)) as BANK_AMT
from
(select
dq.operating_unit as BU,
dq.grp_brn_id as GPBR,
dq.stn_id as STN_ID,
qd.department as DEPTID,
qd.ecr_ticket_no as TICKET_NUM,
qd.open_item_id,
qd.rnt_agr_nbr,
cast(qd.monetary_amount as decimal (15,2)) as GL_AMT
from
qry_drvd qd,
drvd_qry dq
where dq.ecr_dept_id = qd.department ) aa
left outer join rfs.pymts p on p.ecr_pymt_id = cast(aa.open_item_id as decimal(19,0))
and p.ram_rea_rnt_agr_nbr = aa.rnt_agr_nbr) bb
left outer join paymt.fin_tran ft on ft.fin_tran_ref_id = bb.fin_tran_ref_id
UNION
select
b.BU,
b.GPBR,
b.STN_ID,
b.DEPTID,
cast(b.MERCH_NUM as decimal(20,0)),
qd.ecr_ticket_no as TICKET_NUM,
b.FIRST6,
b.LAST4,
b.AUTH_NUM,
cast(b.REF_NUM as decimal(20,0)),
b.GL_AMT,
b.BANK_AMT
from
(select
a.BU,
a.GPBR,
a.STN_ID,
a.DEPTID,
a.MERCH_NUM,
a.REF_NUM,
a.FIRST6,
a.LAST4,
p.auth_nbr as AUTH_NUM,
p.ecr_pymt_id,
a.GL_AMT,
a.BANK_AMT
from
(select
dq.operating_unit as BU,
dq.grp_brn_id as GPBR,
dq.stn_id as STN_ID,
dq.ecr_dept_id as DEPTID,
cast(f.merch_num as varchar(20)) as MERCH_NUM,
f.ret_ref_num as REF_NUM,
ft.prim_acct_frst_six_dgt_nbr as FIRST6,
ft.prim_acct_last_four_dgt_nbr as LAST4,
CAST(0 AS DECIMAL(15,2)) as GL_AMT,
cast(case when f.tran_typ_cde = 1 then f.tran_amt
when f.tran_typ_cde = 4 then f.tran_amt * -1
end as decimal (15,2)) as BANK_AMT,
ft.fin_tran_ref_id
from paymt.fndng_recncl_dtl_rprt f,
rfs.cc_mrchnt_nbr m,
drvd_qry dq,
paymt.fin_tran ft
--rfs.pymts p
where f.row_stat_cde = 'A'
and cast (f.tran_proc_date as date format 'MM/DD/YYYY') = '09/23/2015'
and m.mrchnt_nbr = f.merch_num
and m.credit_card_typ = 'VI'
and dq.stn_id = m.sta_stn_id
and ft.stlmt_uniq_ref_nbr = f.ret_ref_num
group by
dq.operating_unit,
dq.grp_brn_id,
dq.stn_id,
dq.ecr_dept_id ,
f.merch_num,
f.ret_ref_num,
ft.prim_acct_frst_six_dgt_nbr,
ft.prim_acct_last_four_dgt_nbr,
GL_AMT,
BANK_AMT,
ft.fin_tran_ref_id) a
left outer join rfs.pymts p on p.fin_tran_ref_id = a.fin_tran_ref_id) b
left outer join qry_drvd qd on cast(qd.open_item_id as decimal(19,0)) = b.ecr_pymt_id
答案 0 :(得分：2)
执行union，然后使用group by，因为虚拟字段0使用SUM加入两行
SELECT "Group", "Branch", "Ref Num", SUM("GL Amt"), SUM("Bank Amt")
FROM (
SELECT * FROM YourQuery1
UNION ALL
SELECT * FROM YourQuery2
) as t
GROUP BY
"Group", "Branch", "Ref Num"
答案 1 :(得分：0)
由于数据来自两个不同的表，然后我认为通过联合进行分组将无法帮助，因为使用with子句的派生表不能在子查询中使用。如果可能将此数据加载到易失性表中，然后按组进行分组并找到最大值（“GL Amt”），（“Bank Amt”）和/或创建一个视图然后查询...