我有一个辅助功能:
namespace PublicationSystem.Tools
{
public class Format
{
public static string FullName(string salutation,
string first,
string middle,
string last,
string suffix = "")
{
var fullName = new StringBuilder();
if (!string.IsNullOrEmpty(salutation)) fullName.Append(salutation + " ");
fullName.Append(first + " ");
if (!string.IsNullOrEmpty(middle)) fullName.Append(middle.Trim() + " ");
fullName.Append(last);
if (!string.IsNullOrEmpty(suffix)) fullName.Append(" " + suffix);
return fullName.ToString().Trim();
}
}
}
我很想在Linq查询中使用它,如下所示:
SessionUser = (
from pi in db.ProfileIdentifier
join p in db.Profile on pi.ProfileId equals p.ProfileId
where
pi.ProfileIdentifierTypeId == (int)ProfileIdentifierTypes.email &&
pi.ProfileIdentifierValue == email &&
pi.IsActive
select new LoginViewModel
{
ProfileId = p.ProfileId,
SessionId = sessionTokenId,
FullName = Format.FullName(p.Salutation,p.FirstName,p.MiddleName,p.LastName),
Email = email,
Permissions = (
from ra in db.RoleAssignment
join rp in db.RolePermission on ra.RoleId equals rp.RoleId
join perm in db.Permission on rp.PermissionId equals perm.PermissionId
where ra.AssigneeId == p.ProfileId &&
rp.IsActive
select new ProfilePermission
{
RoleId = ra.RoleId,
AssignedToId = ra.AssignedToId,
PermissionId = perm.PermissionId,
PermissionName = perm.PermissionName,
PermissionGroupId = perm.PermissionGroupId
}).ToList()
}).FirstOrDefault();
有没有办法做到这一点?
答案 0 :(得分:0)
是的,但是在查询数据源(例如SQL Server)时,该提供程序将不知道如何处理您的函数。
您可以在查询中使用.AsEnumerable(),以便在客户端而不是在数据库中评估该查询的其余部分。在调用.AsEnumerable()之后,您可以使用自己的函数,例如Format.FullName()。
请注意,在完成可在数据库中完成的过滤之前,应避免调用.AsEnumerable(),因为该调用之后的所有数据都会从数据库传输到客户端程序。
答案 1 :(得分:0)
Linq To Sql不知道如何将方法FullName(..)
的内容解析为sql。
您可以执行查询,返回匿名对象,示例:
var tempUser = (
from pi in db.ProfileIdentifier
join p in db.Profile on pi.ProfileId equals p.ProfileId
where
pi.ProfileIdentifierTypeId == (int)ProfileIdentifierTypes.email &&
pi.ProfileIdentifierValue == email &&
pi.IsActive
select new
{
p.ProfileId,
SessionId = sessionTokenId,
p.Salutation,
p.FirstName,
p.MiddleName,
p.LastName,
Email = email
}).FirstOrDefault();
之后,您可以使用函数FullName(..)
转换结果,样本:
if (tempUser != null)
{
SessionUser = new LoginViewModel
{
ProfileId = tempUser.ProfileId,
SessionId = tempUser.SessionId,
FullName = Format.FullName(tempUser.Salutation, tempUser.FirstName, tempUser.MiddleName, tempUser.LastName),
Email = tempUser.Email
};
}
答案 2 :(得分:-1)
这是最简单的转换:
SessionUser = (
from pi in db.ProfileIdentifier
join p in db.Profile on pi.ProfileId equals p.ProfileId
where
pi.ProfileIdentifierTypeId == (int)ProfileIdentifierTypes.email &&
pi.ProfileIdentifierValue == email &&
pi.IsActive
select p)
.ToList()
.Select(p=>new LoginViewModel
{
ProfileId = p.ProfileId,
SessionId = sessionTokenId,
FullName = Format.FullName(p.Salutation,p.FirstName,p.MiddleName,p.LastName),
Email = email
}).FirstOrDefault();
这会更有效:
SessionUser = (
from pi in db.ProfileIdentifier
join p in db.Profile on pi.ProfileId equals p.ProfileId
where
pi.ProfileIdentifierTypeId == (int)ProfileIdentifierTypes.email &&
pi.ProfileIdentifierValue == email &&
pi.IsActive
select p)
.Take(1)
.ToList()
.Select(p=>new LoginViewModel
{
ProfileId = p.ProfileId,
SessionId = sessionTokenId,
FullName = Format.FullName(p.Salutation,p.FirstName,p.MiddleName,p.LastName),
Email = email
}).FirstOrDefault();
效率更高:
SessionUser = (
from pi in db.ProfileIdentifier
join p in db.Profile on pi.ProfileId equals p.ProfileId
where
pi.ProfileIdentifierTypeId == (int)ProfileIdentifierTypes.email &&
pi.ProfileIdentifierValue == email &&
pi.IsActive
select new
{
p.ProfileId,
p.Salutation,
p.FirstName,
p.MiddleName,
p.LastName
})
.Take(1)
.ToList()
.Select(p=>new LoginViewModel
{
ProfileId = p.ProfileId,
SessionId = sessionTokenId,
FullName = Format.FullName(p.Salutation,p.FirstName,p.MiddleName,p.LastName),
Email = email
}).FirstOrDefault();