Question

增量$ i不在函数中返回1 ++

function show7days()
{
    $sql = mysql_query("SELECT * FROM `movies` WHERE dateuploaded >= DATE_SUB(NOW(), INTERVAL 7 DAY) order by visits desc LIMIT 7");
    while ($row=mysql_fetch_array($sql)) {
        $name = $row[2];
        $descr = $row[3];
        $img = $row[4];
        $i=1;
        echo "<p align=\"center\">$i.$i++<a href=\"/movie/".($row[2])."\"><img src=\"/movie/".($img)."\ height=\"30\" width=\"30\";></a><br><a href=\"/movie/$row[2]\">$name</a></p>";
    }
}

Answer 1

每次因为在循环内初始化而得到相同的值。你错过了报价。

$i=1;// keep this outside.
while($row=mysql_fetch_array($sql)) {
    $name = $row[2];
    $descr = $row[3];
    $img = $row[4];

    echo "<p align=\"center\">".$i++."<a href=\"/movie/".($row[2])."\"><img src=\"/movie/".($img)."\ height=\"30\" width=\"30\";></a><br><a href=\"/movie/$row[2]\">$name</a></p>";
                              ^     ^//missed the quotes aswell
  }

Answer 2

 $i=1;
 $sql = mysql_query("SELECT * FROM `movies` WHERE dateuploaded >= DATE_SUB(NOW(), INTERVAL 7 DAY) order by visits desc LIMIT 7");
      while($row=mysql_fetch_array($sql)) {
    $name = $row[2];
    $descr = $row[3];
    $img = $row[4];
            echo "<p align=\"center\">$i.$i++<a href=\"/movie/".($row[2])."\"><img src=\"/movie/".($img)."\ height=\"30\" width=\"30\";></a><br><a href=\"/movie/$row[2]\">$name</a></p>";
      }
    }

It may solve your problem

增量不起作用

2 个答案: