Question

我有一项任务必须在今天完成，我需要你的帮助

我想要一个swift 2的代码，让json发布到api 我尝试了许多maaany代码，但没有任何工作，我也找到了String post的工作代码，但它并没有帮助我很多，

我编写了这段代码，但是有一个错误:(

  let request = NSMutableURLRequest(URL: NSURL(string: url)!)
    let session = NSURLSession.sharedSession()
    let jsonString : NSString = "{\"Authentication\":{\"Username\":\"\(usernameTextField.text)\",\"Password\":\"\(passwordTextField.text)\"},\"RequestType\":7}"
    request.HTTPMethod = "POST"

    //request.HTTPBody = jsonString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: true)
    request.addValue("application/json", forHTTPHeaderField: "Content-Type")
    request.addValue("application/json", forHTTPHeaderField: "Accept")


    do {
        let param = jsonString.dataUsingEncoding(NSUTF8StringEncoding)
        request.HTTPBody = try NSJSONSerialization.dataWithJSONObject(param!, options: [])
    } catch {
        print(error)
        request.HTTPBody = nil
    }


        let task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
            // handle error
            guard error == nil
                else
            {
                return
            }
            print("Response: \(response)")
            let strData = NSString(data: data!, encoding: NSUTF8StringEncoding)
            print("Body: \(strData)")
            let json: NSDictionary?
            do {
                json = try NSJSONSerialization.JSONObjectWithData(data!, options: .MutableLeaves) as? NSDictionary
            } catch let dataError {
                // Did the JSONObjectWithData constructor return an error? If so, log the error to the console
                print(dataError)
                let jsonStr = NSString(data: data!, encoding: NSUTF8StringEncoding)
                print("Error could not parse JSON: '\(jsonStr)'")
                // return or throw?
                return
            }


            // The JSONObjectWithData constructor didn't return an error. But, we should still
            // check and make sure that json has a value using optional binding.
            if let parseJSON = json {
                // Okay, the parsedJSON is here, let's get the value for 'success' out of it
                let success = parseJSON["success"] as? Int
                print("Succes: \(success)")
            }
            else {
                // Woa, okay the json object was nil, something went worng. Maybe the server isn't running?
                let jsonStr = NSString(data: data!, encoding: NSUTF8StringEncoding)
                print("Error could not parse JSON: \(jsonStr)")
            }

        })

        task.resume()

所以请帮忙吗？

Answer 1

为NSJSONSerialization.dataWithJSONObject提供字典而不是字符串

类似于此：

let jsonObj = ["Param1":"Value2", "Param2":"value2"]
NSJSONSerialization.dataWithJSONObject(jsonObj, options: [])

Swift 2制作Post Json

1 个答案: