Question

我有两张桌子

_id___|_description___
3433  | Apple-Pie
3699  | Strawberry-Pie
6952  | Banana-Pie
...

和

_cakeId__|_ ingredientCode _
3433     | SUGAR
3433     | APPLE
3433     | E_200_SRT_05
3433     | CREAM
3699     | SUGAR
3699     | STRABERRY
6952     | E_200_SRT_08
6952     | E_200_KJ_84
...

我现在想要在成分表中选择 0条的所有蛋糕（按id），而以E_开头的成分不计算。

在上面的示例中，只会选择ID为 6952 的蛋糕。

我尝试了几种连接和子选择计数的组合，但我从来没有得到正确的结果

select 
    c.id
    t1.cntIngr
from 
    cakes c 

join (
    select 
        cakeId,
        count(ingredientCode) as cntIngr
    from 
        cake_ingredients    
    group by cakeId
    having ingredientCode not like 'E_%'

) as t1 on t1.cakeId = c.id

Answer 1

http://sqlfiddle.com/#!9/d3d375/2

SELECT c.*
FROM cakes c
LEFT JOIN cake_ingredients i
ON i.cakeId = c.id
  AND LEFT(i.ingredientCode,2)<>'E_'
WHERE i.cakeId IS NULL

Answer 2

尝试此查询

SELECT description
FROM tab1
INNER JOIN (SELECT cakeId, COUNT(ingredientCode)
           FROM tab2
           WHERE ingredientCode NOT LIKE "E_%"
           GROUP BY cakeId
           HAVING COUNT(ingredientCode) = 0) AS tab2
ON tab1.id = tab2.cakeId

Answer 3

这是一个不存在的查询：你想要所有没有非E成分的蛋糕：

select id
from cakes c
where not exists
(
  select *
  from cake_ingredients ci
  where ci.ingredientcode not like 'E\_%' escape '\'
  and ci.cakeId = c.id
);

与NOT IN：

相同

select id
from cakes
where id not in
(
  select cakeId
  from cake_ingredients
  where ingredientcode not like 'E\_%' escape '\'
);

（因为它的简单性，我通常更喜欢NOT IN而不是NOT EXISTS。）

Answer 4

http://sqlfiddle.com/#!9/8f850/5

MySQL，选择在其他表中没有总和的所有内容

4 个答案: