如何从列表中序列化一个类?

时间:2015-10-28 14:45:57

标签: c#

我有一个班级列表,我想知道如何将其序列化为XElement

例如我有一个班级:

    [DataContract]
    public class Order 
    {
        [DataMember]
        public int OrderId { get; set; }

        [DataMember]
        public string OrderTitle { get; set; }

        [DataMember]
        public string DestinationAddress { get; set; }

        [DataMember]
        public string PhoneNumber { get; set; }
    }

现在我有一个上面的类列表,我想知道如何序列化它?

2 个答案:

答案 0 :(得分:2)

enter var templates = from t in response.Descendants("OrderList")
                                    select new
                                    {
                                        orderId = t.Element("OrderId").Value.ToString(),
                                        orderTitle = t.Element("OrderTitle").Value.ToString(),
                                        DestinationAddress = t.Element("DestinationAddress").Value.ToString(),
                                        PhoneNumber = t.Element("PhoneNumber").Value.ToString()
                                    };code here

按上述方式执行arrayOfNotaryOrderDocumentsSet.ToList()作为您的订单列表,您可以根据需要选择节点名称。我给了Order

答案 1 :(得分:1)

构建列表List<Order> ..使用Serializator类(来自代码项目)

public class Serializator
{
    public static string SerializeLinqList<T>(List<T> list)
    {
        DataContractSerializer dcs = new DataContractSerializer(typeof(List<T>));
        StringBuilder sb = new StringBuilder();
        using (XmlWriter writer = XmlWriter.Create(sb))
        {
            dcs.WriteObject(writer, list);
        }
        return sb.ToString();
    }

    public static List<T> DeserializeLinqList<T>(string xml)
    {
        List<T> list;

        DataContractSerializer dcs = new DataContractSerializer(typeof(List<T>));

        using (XmlReader reader = XmlReader.Create(new StringReader(xml)))
        {
            list = dcs.ReadObject(reader) as List<T>;
        }
        if (list == null) list = new List<T>();
        return list;
    }
}