Question

我有这个查询给出了年份之和，但我想在每个 TARMA 的末尾添加一个新行，它们给出了年份之间的差异。

以下是查询：

 Select  
     VPC.Armazem as TARMA
    ,YEAR(VPC.DATA) as DataTotal
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 1 THEN VPL.QTD ELSE 0 END) as ADITIVADA
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 2 THEN VPL.QTD ELSE 0 END) as X98
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 3 THEN VPL.QTD ELSE 0 END)as X95
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 4 THEN VPL.QTD ELSE 0 END) as XGAS
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 5 THEN VPL.QTD ELSE 0 END) as XGPL
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 6 THEN VPL.QTD ELSE 0 END) as XAGR
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 7 THEN VPL.QTD ELSE 0 END) as MISTURA
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 9 THEN VPL.QTD ELSE 0 END) as XAQ
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 10 THEN VPL.QTD ELSE 0 END) as ADIESEL
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 11 THEN VPL.QTD ELSE 0 END) as ADBLUE
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 12 THEN VPL.QTD ELSE 0 END) as O95
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 13 THEN VPL.QTD ELSE 0 END) as O98
FROM
    CB_VendasPOS (nolock) as VP
    INNER JOIN Vendaspos_Linhas (nolock) as VPL on VPL.Autoreg=VP.AutoReg
    INNER JOIN VendasPOS_Cabecalhos (nolock) as VPC on VPC.Prenumero=VPL.Prenumero
    INNER JOIN VendasPOS_Turnos (nolock) as VPT on VPT.CodTurnoAuto=VPC.CodTurnoAuto
WHERE 
    (MONTH(VPC.DATA) >= MONTH('2015-09-01') AND MONTH(VPC.DATA) <= MONTH('2015-09-30'))
    and (YEAR(VPC.DATA) >= YEAR('2014-09-01') AND YEAR(VPC.DATA) <= YEAR('2015-09-30'))
    and VPT.armazem IN ('454','457')
    and FACT_VD NOT IN ('A', 'I', 'G', 'M')
GROUP BY
    YEAR(VPC.DATA)
    ,VPC.Armazem
ORDER BY
    VPC.Armazem
    ,YEAR(VPC.DATA)

这是没有区别的结果： Result

例如：

TARMA：X98为454

2014：1849.14077

2015：2571.47750

差异：-722,33673

我正在使用MS SQL。它是UNION吗？

我怎样才能有所不同？

Answer 1

将您的查询用作子查询（不包含order by），您可以执行以下操作：

with cte as (
      <your query here>
     )
select cte.*,
       (additava - lag(additava) over (partition by Armazem order by DataTotal) ) as additava_diff,
       . . .
from cte;

注意：lag()需要SQL Server 2012 +。

编辑：

在SQL Server 2012+之前，您可以这样做：

with cte as (
      <your query here>
     )
select cte.*,
       (additava - cte2.additava) as additava_diff,
       . . .
from cte outer apply
     (select top 1 cte.*
      from cte cte2
      where cte2.Armazem = cte.Armazem and cte2.DataTotal < cte.DataTotal
      order by cte2.DataTotal
     ) cte2

Answer 2

如果要在单独的查询中计算差异，然后只是将行“添加”到结果中，则可以在查询之间使用“UNION ALL”。 “UNION ALL”将只合并2个结果集。仅使用“UNION”将导致SQL Server尝试对2个结果集中的行进行重复数据删除。

Answer 3

我明白了：

;with dados as (

    Select  
     VPC.Armazem as TARMA
    ,YEAR(VPC.DATA) as DataTotal1
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 1 THEN VPL.QTD ELSE 0 END) as SomaADITIVADA
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 2 THEN VPL.QTD ELSE 0 END) as SomaX98
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 3 THEN VPL.QTD ELSE 0 END)as SomaX95
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 4 THEN VPL.QTD ELSE 0 END) as SomaXGAS
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 5 THEN VPL.QTD ELSE 0 END) as SomaXGPL
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 6 THEN VPL.QTD ELSE 0 END) as SomaXAGR
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 7 THEN VPL.QTD ELSE 0 END) as SomaMISTURA
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 9 THEN VPL.QTD ELSE 0 END) as SomaXAQ
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 10 THEN VPL.QTD ELSE 0 END) as SomaADIESEL
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 11 THEN VPL.QTD ELSE 0 END) as SomaADBLUE
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 12 THEN VPL.QTD ELSE 0 END) as SomaO95
    ,SUM(CASE WHEN VP.COMBUSTIVEL = 13 THEN VPL.QTD ELSE 0 END) as SomaO98
    ,row_number() over (partition by VPC.Armazem order by YEAR(VPC.DATA) ASC) as NAno
FROM
    CB_VendasPOS (nolock) as VP
    INNER JOIN VendasPOS_Linhas (nolock) as VPL on VPL.Autoreg=VP.AutoReg
    INNER JOIN VendasPOS_Cabecalhos (nolock) as VPC on VPC.Prenumero=VPL.Prenumero
    INNER JOIN VendasPOS_Turnos (nolock) as VPT on VPT.CodTurnoAuto=VPC.CodTurnoAuto
WHERE 
    (MONTH(VPC.DATA) >= MONTH('2015-09-01') AND MONTH(VPC.DATA) <= MONTH('2015-09-30'))
    and (YEAR(VPC.DATA) >= YEAR('2014-09-01') AND YEAR(VPC.DATA) <= YEAR('2015-09-30'))
    and VPT.armazem IN ('454','457')
    and FACT_VD NOT IN ('A', 'I', 'G', 'M')
GROUP BY
    YEAR(VPC.DATA)
    ,VPC.Armazem

)

SELECT
      anosDetalhados.TARMA as TARMA
     ,anosDetalhados.DataTotal1 as DataTotal
     ,SUM(anosDetalhados.SomaADITIVADA) as ADITIVADA 
     ,SUM(anosDetalhados.SomaX98) as X98
     ,SUM(anosDetalhados.SomaX95) as X95
     ,SUM(anosDetalhados.SomaXGAS) as XGAS
     ,SUM(anosDetalhados.SomaXGPL) as XGPL
     ,SUM(anosDetalhados.SomaXAGR) as XAGR
     ,SUM(anosDetalhados.SomaMISTURA) as MISTURA
     ,SUM(anosDetalhados.SomaXAQ) as XAQ
     ,SUM(anosDetalhados.SomaADIESEL) as ADIESEL
     ,SUM(anosDetalhados.SomaADBLUE) as ADBLUE
     ,SUM(anosDetalhados.SomaO95) as O95
     ,SUM(anosDetalhados.SomaO98) as O98
FROM dados as anosDetalhados (nolock)
GROUP BY
    anosDetalhados.DataTotal1
    ,anosDetalhados.TARMA

UNION ALL

SELECT
     ano1.TARMA as TARMA
    ,NULL  as DataTotal
    ,SUM(coalesce(ano1.SomaADITIVADA-ano2.SomaADITIVADA, 0)) as ADITIVADA 
    ,SUM(coalesce(ano1.SomaX98-ano2.SomaX98, 0)) as X98
    ,SUM(coalesce(ano1.SomaX95-ano2.SomaX95, 0)) as X95
    ,SUM(coalesce(ano1.SomaXGAS-ano2.SomaXGAS, 0)) as XGAS
    ,SUM(coalesce(ano1.SomaXGPL-ano2.SomaXGPL, 0)) as XGPL
    ,SUM(coalesce(ano1.SomaXAGR-ano2.SomaXAGR, 0)) as XAGR
    ,SUM(coalesce(ano1.SomaMISTURA-ano2.SomaMISTURA, 0)) as MISTURA
    ,SUM(coalesce(ano1.SomaXAQ-ano2.SomaXAQ, 0)) as XAQ
    ,SUM(coalesce(ano1.SomaADIESEL-ano2.SomaADIESEL, 0)) as ADIESEL
    ,SUM(coalesce(ano1.SomaADBLUE-ano2.SomaADBLUE, 0)) as ADBLUE
    ,SUM(coalesce(ano1.SomaO95-ano2.SomaO95, 0)) as O95
    ,SUM(coalesce(ano1.SomaO98-ano2.SomaO98, 0)) as O98
FROM dados as ano1 (nolock)
LEFT JOIN dados as ano2 on ano1.TARMA=ano2.TARMA and ano1.NAno > ano2.NAno
GROUP BY
    ano1.TARMA
ORDER BY
    TARMA
   ,anosDetalhados.DataTotal1 ASC

SQL选择添加数字之间存在差异的新行

3 个答案: