我正在尝试让Pin进入页面,我创建了4个EditTexts,并在我的活动中创建了一个函数。我的问题是,当我单击退格按钮时,我想将当前EditText聚焦到Before(Back)EditText,但Key监听器不起作用。
逻辑很简单,当用户输入一个编号来编辑文本时,它会失去焦点,然后编辑文本会得到焦点,然后就是这样。但问题是当我点击后退空间我想在edittext之前返回再次输入数字。我试图在beforeTextChange中插入keyListener,但它没有工作。
private void SetTextChange(final EditText etCurrent, final EditText etForward,final EditText etBack, final boolean isLast, final int currentPosition)
{
etCurrent.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
if (etCurrent.getText().length() == 1 && !isLast ) {
etCurrent.setTypeface(null, Typeface.NORMAL);
etCurrent.clearFocus();
etForward.requestFocus();
etForward.setCursorVisible(true);
etCurrent.getBackground().setColorFilter(getResources().getColor(R.color.lavender_indigo), PorterDuff.Mode.SRC_ATOP);
} else if (etCurrent.length() == 0) {
etCurrent.getBackground().setColorFilter(getResources().getColor(R.color.french_gray), PorterDuff.Mode.SRC_ATOP);
etCurrent.setTypeface(null, Typeface.SANS_SERIF.getStyle());
etCurrent.setTypeface(null, Typeface.NORMAL);
etCurrent.clearFocus();
etBack.requestFocus();
etBack.setCursorVisible(true);
}
if (etCurrent.length() != 0) {
Integer currentKey = Integer.parseInt(etCurrent.getText().toString());
keyList.set(currentPosition, currentKey);
} else
keyList.set(currentPosition, -1);
if (keyList.size() > 3)
showToast(keyList.get(0) + " " + keyList.get(1) + " " + keyList.get(2) + " " + keyList.get(3));
}
@Override
public void afterTextChanged(Editable s) {
}
});
/*curText.setOnFocusChangeListener(new View.OnFocusChangeListener() {
public void onFocusChange(View arg0, boolean arg1) {
curText = etCurrent;
backText = etBack;
curText.setText("");
}
});*/
}
这也是我的EditText示例xml之一。(其他是相同的)
<EditText
android:layout_column="1"
android:layout_columnWeight="1"
android:id="@+id/etActivationDigit1"
android:layout_width="70dp"
android:layout_height="wrap_content"
android:textSize="80dp"
android:textAlignment="center"
android:gravity="center_horizontal"
android:hint="*"
android:textColorHint="@color/french_gray"
android:backgroundTint="@color/french_gray"
android:fontFamily="sans-serif"
android:textColor="@color/perfume"
android:maxLength="1"
android:inputType="number"
/>
我只是想在用户输入错误号码时擦除并重新聚焦。注意:当你填写所有字段时,你会看到你可以删除并返回,但我想回到密码的中间位置。谢谢。
etCurrent.setOnKeyListener(new View.OnKeyListener() {
@Override
public boolean onKey(View v, int keyCode, KeyEvent event) {
if(etCurrent.getText().toString() == "" && keyCode == event.KEYCODE_DEL)
{
etCurrent.setText("");
etCurrent.clearFocus();
etBack.requestFocus();
etBack.setText("");
}
return false;
}
});
当我触摸退格键时,我的Backspace侦听器不会触发,但会触发所有其他字符。
答案 0 :(得分:2)
这适用于我的4位密码活动。
private void setupInputListeners() {
verificationCode1EditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
if (s.length() == 1) {
verificationCode2EditText.requestFocus(View.FOCUS_DOWN);
}
}
@Override
public void afterTextChanged(Editable s) {
}
});
verificationCode2EditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
if(count == 0) {
verificationCode1EditText.requestFocus(View.FOCUS_DOWN);
} else {
if (s.length() == 1) {
verificationCode3EditText.requestFocus(View.FOCUS_DOWN);
}
}
}
@Override
public void afterTextChanged(Editable s) {
}
});
verificationCode3EditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
if(count == 0) {
verificationCode2EditText.requestFocus(View.FOCUS_DOWN);
} else {
if (s.length() == 1) {
verificationCode4EditText.requestFocus(View.FOCUS_DOWN);
}
}
}
@Override
public void afterTextChanged(Editable s) {
}
});
verificationCode4EditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
if(count == 0) {
verificationCode3EditText.requestFocus(View.FOCUS_DOWN);
}
}
@Override
public void afterTextChanged(Editable s) {
}
});
}
答案 1 :(得分:0)
看看这个。
MainActivity.java
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
final EditText one = (EditText) findViewById(R.id.edtOne);
final EditText two = (EditText) findViewById(R.id.edtTwo);
final EditText three = (EditText) findViewById(R.id.edtThree);
final EditText four = (EditText) findViewById(R.id.edtFour);
one.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) {
// TODO Auto-generated method stub
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable s) {
// TODO Auto-generated method stub
}
});
two.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) {
if(s.toString().trim().length() == 0){
one.requestFocus();
one.setSelection(one.getText().toString().length());
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable s) {
// TODO Auto-generated method stub
}
});
three.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) {
if(s.toString().trim().length() == 0){
two.requestFocus();
two.setSelection(two.getText().toString().length());
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable s) {
// TODO Auto-generated method stub
}
});
four.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) {
if(s.toString().trim().length() == 0){
three.requestFocus();
three.setSelection(three.getText().toString().length());
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable s) {
// TODO Auto-generated method stub
}
});
}
}
//使用此代码作为参考。
customDialog.setOnKeyListener(new OnKeyListener() {
@Override
public boolean onKey(DialogInterface dialog, int keyCode, KeyEvent event) {
if (event.getAction() != KeyEvent.ACTION_DOWN) {
if (keyCode == KeyEvent.KEYCODE_BACK) {
customDialog.dismiss();
HomeActivity.this.finish();
} else if (keyCode == KeyEvent.KEYCODE_DEL) {
if (!pin3.getText().toString().equals("")) {
pin3.setText("");
pin3.requestFocus();
} else if (!pin2.getText().toString().equals("")) {
pin2.setText("");
pin2.requestFocus();
} else if (!pin1.getText().toString().equals("")) {
pin1.setText("");
pin1.requestFocus();
}
}
}
return true;
}
});
return customDialog;
我在我的应用程序中使用此代码,它完全有效。
activity_main.xml中
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
<EditText
android:id="@+id/edtOne"
android:layout_width="100dp"
android:layout_height="wrap_content"
android:text="0" />
<EditText
android:id="@+id/edtTwo"
android:layout_width="100dp"
android:layout_height="wrap_content"
android:text="2" />
<EditText
android:id="@+id/edtThree"
android:layout_width="100dp"
android:layout_height="wrap_content"
android:text="3" />
<EditText
android:id="@+id/edtFour"
android:layout_width="100dp"
android:layout_height="wrap_content"
android:text="4" />
</LinearLayout>
答案 2 :(得分:0)
只需将此代码添加到您的editText onTextChanged方法中
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
if(yourEditText.length()==0){
priviousEditText.requestFocus();
}
}
答案 3 :(得分:0)
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_DEL) {
if (mPineighthDigitEditText.getText().length() ==0 )
{ //mPineighthDigitEditText.setText("");
mPinseventthDigitEditText.requestFocus();
}
if (mPinseventthDigitEditText.getText().length() == 0){
// mPinseventthDigitEditText.setText("");
mPinsixthDigitEditText.requestFocus();}
if (mPinsixthDigitEditText.getText().length() == 0) {
// mPinsixthDigitEditText.setText("");
mPinFifthDigitEditText.requestFocus();}
if (mPinFifthDigitEditText.getText().length() == 0){
//mPinFifthDigitEditText.setText("");
mPinForthDigitEditText.requestFocus();}
if (mPinForthDigitEditText.getText().length() == 0){
// mPinForthDigitEditText.setText("");
mPinThirdDigitEditText.requestFocus();}
if (mPinThirdDigitEditText.getText().length() == 0){
//mPinThirdDigitEditText.setText("");
mPinSecondDigitEditText.requestFocus();}
if (mPinSecondDigitEditText.getText().length() == 0){
//mPinSecondDigitEditText.setText("");
mPinFirstDigitEditText.requestFocus();}
if (mPinFirstDigitEditText.getText().length() == 0 ) {
mPinFirstDigitEditText.setText("");
}
return true;
}
return super.onKeyDown(keyCode, event);
}
}
如果提交了多个编辑文本,谢谢:)
答案 4 :(得分:0)
以为 OTP 填充 4 个 editText 的示例编写此答案。
首先创建一个包含 4 个 editText 的数组并将它们与视图绑定
private var otpPins = arrayOfNulls<EditText>(4) //remember to input maxlenght = 1 in each view in xml file
otpPins[0] = findViewById(R.id.otp_1)
otpPins[1] = findViewById(R.id.otp_2)
otpPins[2] = findViewById(R.id.otp_3)
otpPins[3] = findViewById(R.id.otp_4)
然后添加textWatcher,这样当输入任意数字时焦点会改变到下一个editText
otpPins[0]?.addTextChangedListener(object : TextWatcher {
override fun afterTextChanged(s: Editable?) {
}
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
}
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
if (s?.length ?: 0 >= 1) {
otpPins[1]?.requestFocus()
}
}
})
otpPins[1]?.addTextChangedListener(object : TextWatcher {
override fun afterTextChanged(s: Editable?) {
}
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
}
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
if (s?.length ?: 0 >= 1) {
otpPins[2]?.requestFocus()
}
}
})
otpPins[2]?.addTextChangedListener(object : TextWatcher {
override fun afterTextChanged(s: Editable?) {
}
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
}
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
if (s?.length ?: 0 >= 1) {
otpPins[3]?.requestFocus()
}
}
})
otpPins[3]?.addTextChangedListener(object : TextWatcher {
override fun afterTextChanged(s: Editable?) {
}
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
}
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
if (s?.length ?: 0 >= 1) {
verifyOtpAndProceed()
}
}
})
现在创建 1 个内部类来检测退格键并将焦点更改为之前的 editText
inner class PinOnKeyListener internal constructor(private val currentIndex: Int) :
View.OnKeyListener {
override fun onKey(v: View, keyCode: Int, event: KeyEvent): Boolean {
if (keyCode == KeyEvent.KEYCODE_DEL && event.action == KeyEvent.ACTION_DOWN) {
if (otpPins[currentIndex]?.text.toString()
.isEmpty() && currentIndex != 0
) otpPins[currentIndex - 1]?.requestFocus()
}
return false
}
}
为每个 editText 分配 setOnKeyLister
otpPins[0]?.setOnKeyListener(PinOnKeyListener(0))
otpPins[1]?.setOnKeyListener(PinOnKeyListener(1))
otpPins[2]?.setOnKeyListener(PinOnKeyListener(2))
otpPins[3]?.setOnKeyListener(PinOnKeyListener(3))
最终结果将是当您输入任何数字时,焦点将更改为下一个图钉。当按下退格键时,如果有输入,它会简单地擦除它,如果没有输入,它会移动到前一个引脚。
答案 5 :(得分:-1)
只需使用StringBuilder并在此处注明您想要关注退格的editText,如下所示:
StringBuilder sb = new StringBuilder(); //define this inside addTextChangedListner
public void afterTextChanged (Editable s) {
if (sb.length() == 0) {
previousEditText.requestFocus();
}
}