Question

我当前的代码在今天的修改日期工作正常，但是现在我希望我的代码能够复制第1天的数据以及今天的数据。

@ECHO OFF
  FOR /F "tokens=2 delims= " %%V IN ("%DATE%") DO SET TDY=%%V
  xcopy /y "DATA_PATH" "LOCAL_SYSTEM" /d:%TDY%
  SET TDY=

Answer 1

使用BAT / VBS解决方案获取昨天日期的方法：

<强> Yesterday.bat

@echo off
>yesterday.vbs echo wscript.echo DateAdd("d", -1, Date(^)^)

for /f "delims=" %%a in ('cscript /nologo yesterday.vbs') do set "$yesterday=%%a"

Echo Yesterday'Date is ==^> %$Yesterday%

如果您希望直接将/字符替换为-，例如：

<强> Yesterday.bat

@echo off
>yesterday.vbs echo wscript.echo replace((DateAdd("d", -1, Date(^)^)^),"/","-"^)

for /f "delims=" %%a in ('cscript /nologo yesterday.vbs') do set "$yesterday=%%a"

Echo Yesterday'Date is ==^> %$Yesterday%

Answer 2

您需要下载datex.exe：

For /f %%a in ('DateX -o -1 -f yyyymmdd') do Set "PreDate=%%a"

datex用法：

 4:12:56.76 c:\>datex /?
DateX 2.7 - (C) 2004-2010 by Bill Stewart (bstewart@iname.com)

Usage: datex [-d date] [-f format] [-i num] [-o offset] [-t]

-d  Specifies a date.
-f  Specifies the format for the date.
-i  Output the date represented by the specified number (inverse of -t).
-o  Specify a number-of-days difference.
-t  Output the date as a number for comparison purposes.

Without arguments, DateX prints the current date and time.

Xcopy复制第-1天的数据

2 个答案: