我最近发布了一个与另一个Parse CloudCode方法有关的问题,如果错误被抛出 错误:成功/错误未被调用 。我再次遇到这个问题但是使用了不同的方法/场景。
Parse.Cloud.define("background", function(request, response) {
var moments = require("cloud/moments.js");
var now = moments.moment();
var query = new Parse.Query("Group");
query.find({
success: function(results) {
for (var i = 0; i < results.length; i++) {
var object = results[i];
var events = object.get("Events");
var getUsers = false;
for (var q = 0; q < events.length; q++) {
var e = events[q];
if (e.get("date") == now) {
getUsers = true;
break;
}
}
if (getUsers == true) {
for (var q = 0; q < events.length; q++) {
var e = events[q];
if (e.get("date") == now) {
var relation = object.relation("created");
var partOne = e.get("name");
var outString1 = partOne.concat(" is now");
// generate a query based on that relation
var query = relation.query();
Parse.Push.send({
where: query, // Set our Installation query
data: {
alert: outString1
}
}, {
success: function() {
// Push was successful
},
error: function(error) {
// Handle error
}
});
var relation2 = object.relation("joined");
var partOnee = e.get("name");
var outString = partOnee.concat(" is now");
// generate a query based on that relation
var query2 = relation.query();
Parse.Push.send({
where: query2, // Set our Installation query
data: {
alert: outString
}
}, {
success: function() {
// Push was successful
},
error: function(error) {
// Handle error
}
});
e.destroy();
}
}
}
}
}
});
response.success();
});
由于此方法不仅涉及简单的查询和返回(因为它具有for循环等),我对如何实现Parse Promise 强大的东西。如果有人可以帮助我如何实施承诺,那将非常感激。