Question

我有一个需要以下功能的场景：

In View I have call as:
$.ajax({
    type: "POST",
    async: false,
    dataType: 'json',
    url: "ControllerA/ActionA",
    data: { var1: some_value },
    success: function (data) {
        if (data == true) {
            form.submit();
        }
        else if (data == false) {
    }
});

// In ControllerA
public JsonResult ActionA(string var1)
{
    /*
 Some manipulation and calculations
 */
 _slist = RedirectToAction("ActionC", "ControllerB", new { var1 = some_value});
 string = _slist.First().ToString();

    return RedirectToAction("ActionB", "ControllerB", new { var1 = var2 });
}

// In ControllerB
public JsonResult ActionB(string var1)
{
    /*
 Some manipulation and calculations
 */

    return Json(false, JsonRequestBehavior.AllowGet);
}

public SelectList ActionC(string var1)
{    
 /*
 Some manipulation and calculations
 */

 Session["STRING"] = some_value;

 return new SelectList(_storeOrderTimeDictionaryList, "Value", "Key");
}

我在View页面中需要JsonResult，但问题是：

由于RedirectToAction返回redirecttorouteresult我无法直接返回JSonResut
由于我需要ActionC中的Session，我无法实例化Controller和召集行动。

Answer 1

这可能不是最好的方法......

很难说，但是干掉控制器，移出业务逻辑可能有所帮助。看起来您想要维护操作B和C的功能。

$.ajax({
    type: "POST",
    async: false,
    dataType: 'json',
    url: "ControllerA/ActionA",
    data: { var1: some_value },
    success: function (data) {
        if (data == true) {
            form.submit();
        }
        else if (data == false) {
    }
});


public Class CalculationsA
{
   public void DoCalculation() {}
}

public Class CalculationsB
{
   public void DoCalculation() {}
}

public Class CalculationsC
{
   public IQueryable<somethign> DoCalculation() {}
}


//_a is declared in Controller A as CalculationsA
//_b is declared in Controller B as CalculationsB 
//_c is declared in Controller C as CalculationsC

// In ControllerA
public JsonResult ActionA(string var1)
{
  _a.DoCalculation(); 
  _slist = _b.DoCalculation().First().ToString();

  Session["STRING"] = some_value;
  _c.DoCalculation();          

  /* your other logic... */

  return Json(retval, JsonRequestBehavior.AllowGet);
}

// In ControllerB
public JsonResult ActionB(string var1)
{
    _b.DoCalculation();

    return Json(false, JsonRequestBehavior.AllowGet);
}

public SelectList ActionC(string var1)
{    
 _c.DoCalculation();

 Session["STRING"] = some_value;

 return new SelectList(_storeOrderTimeDictionaryList, "Value", "Key");
}

顺便说一下，您应该查看Ninject，Castle Windsor，结构图或任何其他DI / IOC容器，以帮助您测试此逻辑（并使其干燥）。尝试搜索ninject asp.net mvc 2教程

Answer 2

您是否可以不重构控制器操作以将Some manipulation and calculations提取到另一个类或服务层函数调用中。

由于我需要ActionC中的Session，我无法实例化Controller并调用该动作。

没有什么可以阻止您在ControllerA.ActionA中使用会话。以下内容并不准确，但可以帮助您..

public class ControllerA{
    public JsonResult ActionA(string var1)
    {
     /*  Some manipulation and calculations    */
         SomeService service = new SomeService();
         _slist = service.ActionThatDoesStuffForActionC(var1);
         Session["STRING"] = var1;
         var firstItem = _slist.First().ToString();

         SomeOtherService service2 = new SomeOtherService();
         var service2Result = service2.ActionThatDoesStuffForActionB(firstItem);

         // convert service2Result  to a jsonresult here.

         return RedirectToAction("ActionB", "ControllerB", new { var1 = firstItem });
     }
}

public class ControllerB{
     public JsonResult ActionB(string var1)
     {
          /*    Some manipulation and calculations    */
          SomeOtherService service2 = new SomeOtherService();
          var service2Result = service2.ActionThatDoesStuffForActionB(var1);

          return Json(false, JsonRequestBehavior.AllowGet);
     }

    public SelectList ActionC(string var1)
     {    
     /*     Some manipulation and calculations     */
     SomeService service = new SomeService();
     _slist = service.ActionThatDoesStuffInActionC(var1);
     Session["STRING"] = var1;
     return new SelectList(_slist, "Value", "Key");
    }   
}

编辑：查看此处http://www.lostechies.com/blogs/jimmy_bogard/archive/2010/07/23/mvcconf-slides-and-code-posted.aspx的源代码。我认为Jimmy Boggard的方法可能很有用，并为您提供了一种调用“其他控制器”操作的方法。你评论'我无法改变行动的行为。重构它需要时间，我没有。对我而言，这标志着通往不可维护代码的道路。重构，重构，重构 - 现在这样做的好处将在以后的阶段为您节省数小时的心痛。基于这个问题，我认为它已经开始了。

调用另一个控制器的操作并将其结果返回到View

2 个答案: