Question

我想将CLPlacemark格式化为字符串。

众所周知的方法是使用ABCreateStringWithAddressDictionary，但在iOS 9中已弃用。警告告诉我改为使用CNPostalAddressFormatter。

但是，CNPostalAddressFormatter只能格式化CNPostalAddress。无法将CLPlacemark正确转换为CNPostalAddress; CLPlacemark和CNPostalAddress共享这3个属性：country，ISOcountryCode和postalCode。

那么我应该如何将CLPlacemark格式化为现在的字符串？

Answer 1

取地标的addressDictionary并使用其"FormattedAddressLines"键提取地址字符串。请注意，这是字符串行的数组。

（但是，你是正确的，负责转换到Contacts框架的Apple开发人员似乎完全忘记了Address Book和CLPlacemark之间的交换。这是Contacts框架中的一个严重错误 - 许多人中的一个。）

编辑由于我最初发布了这个答案，Apple修复了这个错误。 CLPlacemark现在具有postalAddress属性，这是一个CNPostalAddress，然后您可以使用CNPostalAddressFormatter来获取一个漂亮的多行地址字符串。一定要import Contacts！

Answer 2

Swift 3.0

if let lines = myCLPlacemark.addressDictionary?["FormattedAddressLines"] as? [String] {
    let placeString = lines.joined(separator: ", ")
    // Do your thing
}

Answer 3

Swift 4.1（和3＆amp; 4，保存1行）

我读了一个问题，问我怎样才能实现这个？＆＃39;：

extension String {
    init?(placemark: CLPlacemark?) {
        // Yadda, yadda, yadda
    }
}

两种方法

我第一次去移植AddressDictionary方法，就像其他海报一样。但这意味着失去CNPostalAddress类和格式化程序的功能和灵活性。因此，方法2。

extension String {
    // original method (edited)
    init?(depreciated placemark1: CLPlacemark?) {
    // UPDATE: **addressDictionary depreciated in iOS 11**
        guard
            let myAddressDictionary = placemark1?.addressDictionary,
            let myAddressLines = myAddressDictionary["FormattedAddressLines"] as? [String]
    else { return nil }

        self.init(myAddressLines.joined(separator: " "))
}

    // my preferred method - let CNPostalAddressFormatter do the heavy lifting
    init?(betterMethod placemark2: CLPlacemark?) {
        // where the magic is:
        guard let postalAddress = CNMutablePostalAddress(placemark: placemark2) else { return nil }
        self.init(CNPostalAddressFormatter().string(from: postalAddress))
    }
}

等等，CLPlacemark→CNPostalAddress初始化程序是什么？

extension CNMutablePostalAddress {
    convenience init(placemark: CLPlacemark) {
        self.init()
        street = [placemark.subThoroughfare, placemark.thoroughfare]
            .compactMap { $0 }           // remove nils, so that...
            .joined(separator: " ")      // ...only if both != nil, add a space.
    /*
    // Equivalent street assignment, w/o flatMap + joined:
        if let subThoroughfare = placemark.subThoroughfare,
            let thoroughfare = placemark.thoroughfare {
            street = "\(subThoroughfare) \(thoroughfare)"
        } else {
            street = (placemark.subThoroughfare ?? "") + (placemark.thoroughfare ?? "")
        } 
    */
        city = placemark.locality ?? ""
        state = placemark.administrativeArea ?? ""
        postalCode = placemark.postalCode ?? ""
        country = placemark.country ?? ""
        isoCountryCode = placemark.isoCountryCode ?? ""
        if #available(iOS 10.3, *) {
            subLocality = placemark.subLocality ?? ""
            subAdministrativeArea = placemark.subAdministrativeArea ?? ""
        }
    }
}

用法

func quickAndDirtyDemo() {
    let location = CLLocation(latitude: 38.8977, longitude: -77.0365)

    CLGeocoder().reverseGeocodeLocation(location) { (placemarks, _) in
        if let address = String(depreciated: placemarks?.first) {
            print("\nAddress Dictionary method:\n\(address)") }

        if let address = String(betterMethod: placemarks?.first) {
            print("\nEnumerated init method:\n\(address)") }
    }
}

/* Output:
Address Dictionary method:
The White House 1600 Pennsylvania Ave NW Washington, DC  20500 United States

Enumerated init method:
1600 Pennsylvania Ave NW
Washington DC 20500
United States
*/

直到这里读到的人都会得到一件免费的T恤。（不是真的）

*此代码适用于Swift 3＆amp; 4，除了用于删除nil值的flatMap已在Swift 4.1中被折旧/重命名为compactMap（文档here，或者请参阅SE-187了解原因）。

Answer 4

Swift 3.0助手方法

class func addressFromPlacemark(_ placemark:CLPlacemark)->String{
        var address = ""

        if let name = placemark.addressDictionary?["Name"] as? String {
            address = constructAddressString(address, newString: name)
        }

        if let city = placemark.addressDictionary?["City"] as? String {
            address = constructAddressString(address, newString: city)
        }

        if let state = placemark.addressDictionary?["State"] as? String {
            address = constructAddressString(address, newString: state)
        }

        if let country = placemark.country{
          address = constructAddressString(address, newString: country)
        }

        return address
      }

CLPlacemark在iOS 9中为字符串

4 个答案:

Swift 3.0

Swift 4.1（和3＆amp; 4，保存1行）

我读了一个问题，问我怎样才能实现这个？＆＃39;：

两种方法

用法