Question

我有这个递归函数：

    function displayTreeview($cats,$depth=0)
    {
        //if($depth==0){echo '<ul>';}
        foreach($cats as $cat)
        {
            $hasChildren=count($cat['children'])>0;
            $class = $hasChildren?' class="menu-item-has-children"':'';
            echo '<li'.$class.' data-children="'.count($cat['children']).'">'.$cat['name'];
            if($hasChildren){
             echo '<ul class="dropdown-menu sub-menu">';
             displayTreeview($cat['children'],$depth+1);echo '</ul>';}
             echo '</li>';
        }
        //if($depth==0){echo '</ul>';}
    }

如何将所有html代码放入var并返回？我尝试使用$ var。=来追加，但没有成功获得正确的代码。

Answer 1

    function displayTreeview($cats,$depth=0, $stringBuilder)
    {
        $stringBuilder = '';
        //if($depth==0){echo '<ul>';}
        foreach($cats as $cat)
        {
            $hasChildren=count($cat['children'])>0;
            $class = $hasChildren?' class="menu-item-has-children"':'';
            $stringBuilder .= '<li'.$class.' data-children="'.count($cat['children']).'">'.$cat['name'];
            if($hasChildren){
                $stringBuilder .= '<ul class="dropdown-menu sub-menu">';
                $stringBuilder .= displayTreeview($cat['children'],$depth+1, $stringBuilder);
                $stringBuilder .= '</ul>';
            }
            $stringBuilder .= '</li>';
        }
        //if($depth==0){echo '</ul>';}

        return $stringBuilder;
    }

注意开始时的$stringBuilder = '';（在评论条件之前）。你需要在这里有这个，然后在循环中追加它。按照你的方式，变量在循环的每次运行中都被重置。

Answer 2

只需用字符串追加替换每个回声，例如：

.close_sesame {
 transform: rotatex(180deg);
 z-index: 9999 ;
}

从函数返回内容而不是echo

2 个答案: