我的脚本使用预生成的数据模式按块写入文件块:
# DedupChunk class CTOR:
class DedupChunk:
def __init__(self, chunk_size, chunk_pattern, chunk_position=0, state=DedupChunkStates.PENDING):
self._chunk_size = chunk_size # chunk size in bytes
self._chunk_pattern = chunk_pattern
self._chunk_position = chunk_position
self._state = state
self.mapping = None
@property
def size(self):
return self._chunk_size
@property
def pattern(self):
return self._chunk_pattern
@property
def position(self):
return self._chunk_position
@property
def state(self):
return self._state
...
# Here Chunk object is being initialized (inside other class's CTOR):
chunk_size = random.randint(64, 192) * 1024 # in bytes
while (position + chunk_size) < self.file_size: # generating random chunks number
self.chunks.append(DedupChunk(chunk_size, DedupChunkPattern.get_random_chunk_pattern(), position))
...
# Actual writing
with open(self.path, 'rb+') as f:
for chunk in self.chunks:
f.write(chunk.pattern * (chunk.size // 8))
...
PyCharm
Expected type 'Union[str, bytearray]' got 'int' instead
显示&#34; f.write(chunk.pattern * chunk.size)
&#34;写入方法中的警告
但在删除分区时
chunk.size //= 8
f.write(chunk.pattern * chunk.size)
,或在外面做分工:
{{1}}
警告消失
这里到底发生了什么?
由于
答案 0 :(得分:23)
忽略此警告。 IDE正在最好地猜测(来自有限的信息)关于数据类型在运行时将是什么,但它猜错了。也就是说,如果你不知道实际上是什么东西,那么期望乘以int
的东西会产生int
是相当合理的。
如果您真的想要解决这个问题,请通过为您的班级编写文档字符串(或使用注释提供类型提示)告诉IDE您期望chunk.pattern
的内容。
例如
class DedupChunk:
"""
:type _chunk_pattern: str
... other fields
"""
... # rest of class