Question

我有一个在onCreate方法中创建的listView。如下所示，并从存储过程中读取数据。我使用了CallabeStatement。

protected void onCreate(final Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.type_of_dairy);

    try
    {

        CallableStatement catCallable;
        ConnectionHelper connectionHelper = new ConnectionHelper();
        catCallable = connectionHelper.getConnection().prepareCall("{ CALL SpGetDairyCategory}");
        catCallable.execute();

        resultSet = catCallable.getResultSet();

        setResultSet(resultSet);

        if(getResultSet().next()) {
            do {

                String typeString = resultSet.getString("CategoryName");
                int typeId = resultSet.getInt("CategoryId");
                integerArraList.add(typeId);
                typeArray.add(typeString);
                typeAdapter.getItemViewType(R.id.listView); // adapter for first ListView
                dairyType.setAdapter(typeAdapter);//dairyType is my first List View

            }while(resultSet.next());

        }
    }
    catch (SQLException e)
    {
        Toast.makeText(getApplicationContext(), "Something is  wrong", Toast.LENGTH_LONG).show();

    }

在上面的代码中，我获得了Category Id和name的Id，并将它们传递给两个名为integerArrayList和typeArray的ArrayLists。

我生成了第二个ListView，其中包含我从上面的存储过程中获得的类别ID。我在dairyType（第一个ListView）onClickListener中执行此操作。这是代码

dairyType.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

                try {
                    flavorAapter.clear();
                    CallableStatement proCallable;
                    ConnectionHelper connectionHelper = new ConnectionHelper();
                    proCallable = connectionHelper.getConnection().prepareCall("{call SpGetCategoryProducts(?)}");
                    proCallable.setInt(1, integerArraList.get(dairyType.getCheckedItemPosition())); //integerArrayList contains the categoryId from the first Store Procedure
                    resultSet2 = proCallable.executeQuery();
//The second Stored Procedure get the Id and return some value as you see
                    if (resultSet2.next()) {
                        do {
                            int flavourId;
                            int weitgh;
                            int price;
                            weitgh = resultSet2.getInt("Weight");
                            price = resultSet2.getInt("Price");
                            String flavourString = resultSet2.getString("Name");
                            flavourId = resultSet2.getInt("Id");


                            dairyArray.add(flavourString);

                            idOfCategories.add(flavourId);
                            weightArray.add(weitgh);
                            priceArray.add(price);

                            flavorAapter.getItemViewType(R.id.listView2);
                            dairyFlavour.destroyDrawingCache();
                            dairyFlavour.setAdapter(flavorAapter);

                        } while (resultSet2.next());
                        connectionHelper.closeConnection();
                    } else {
                        flavorAapter.clear();
                        Toast.makeText(getApplicationContext(), "Nothing to show", Toast.LENGTH_LONG).show();

                    }
                } catch (SQLException e) {
                    Toast.makeText(getApplicationContext(), "Something wrong", Toast.LENGTH_LONG).show();
                    dairyArray.clear();
                }
            }
        });

好的，所以我按照自己的意愿成功生成了第二个Listview，问题出在插入Buttom，现在我有名称，重量，价格和Id的ArrayList。（我使用Id作为传递给最后存储过程的参数。所以我必须调用另一个存储过程将所有这些数据插入DB（名称，重量，价格）但它不会插入更改的项值。这意味着，我从第一个ListView中选择一个项目，第二个Listview生成，我选择其中一个，但是当我在第一个ListView中更改我的选择时，它仍然插入第一个ListView的id。这是我的插入代码，通过buttom命名为apply。

    apply.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            try {
                    dairyFlavour.invalidateViews();
                    dairyType.invalidateViews();
                    typeAdapter.notifyDataSetInvalidated();
                    flavorAapter.notifyDataSetChanged();
                    int weight = weightArray.get(dairyFlavour.getCheckedItemPosition()); //weitgh from previous SP
                    int price = priceArray.get(dairyFlavour.getCheckedItemPosition()); //price from previous SP
                    String count = "";
                    int c;
                    count = countOfProduct.getText().toString(); // insert the count of product via editText
                    c = Integer.parseInt(count); // cast the cound to Integer
                    we = idOfCategories.get(dairyFlavour.getCheckedItemPosition());//the id i got in previous SP

                    CallableStatement callableStatement = null;
                    ConnectionHelper connectionHelper = new ConnectionHelper();
                    callableStatement = connectionHelper.getConnection().prepareCall("{call SpInsertLoadCityProducts(?, ?, ? ,?)}");

                    callableStatement.setInt(1, we);
                    callableStatement.setInt(2, weight);
                    callableStatement.setInt(3, price);
                    callableStatement.setInt(4, c);
                    callableStatement.executeQuery();

                }catch(SQLException e){

               Toast.makeText(getApplicationContext(), "Something is wrong", Toast.LENGTH_LONG).show()


            }
            Intent i = new Intent(getApplicationContext(), FinishLoading.class);
            startActivity(i);
        }

    });

在视图中它是可以的，因为我根据需要更改了第一个ListView生成的第二个ListView。但是在insert中，我只将第一个选择的值插入到DB中，当我在第一个ListView中更改选择并在第二个ListView中选择另一个产品并单击apply buttom时，将插入第一个数据。

有什么建议吗？如果你感到困惑，请提出问题，让自己更清楚！

Answer 1

我找到了解决方案。我应该清除每个ArrayList存储数据。当第一次获取索引和数据时，我应该清除ArrayList并再次填写它们，如下所示。

        dairyTypes.clear();
        integerArraList.clear();
        typeArray.clear();

以及

            flavorAapter.clear();

ListView不会在活动onCreate方法或buttom onClickListener方法中更新

1 个答案: