Question

我正在尝试使用Alamofire调用JSON数组中的对象。我可以让Alamofire解析我的文件，但我找不到获取特定参数的方法。

如果我使用：

Alamofire.request(.GET, "https://example.com//users_result.json")
            .responseJSON { response in

                print(response.result)   // result of response serialization

                if let JSON = response.result.value {
                    print(JSON.count)
                    print("JSON: \(JSON[1])")
                }
        }

代码打印出来：

> SUCCESS 4 JSON: {
>     Age = 22;
>     Email = "annahswift@gmail.com";
>     Location = "New York";
>     MyText = "Love Music";
>     Name = Annah;
>     Password = 123456;
>     REF = 003;
>     "Reg_Date" = "2015-07-30";
>     Sex = Female;
>     Surname = Swift; }

现在，我如何调用参数＆＃39; name＆＃39;？

print("JSON: \(JSON[1][4])") // nil ??

Answer 1

RewriteCond %{THE_REQUEST} ^.+?\ [^?]+\.php[?\ ] [NC]
RewriteRule !(^|/)(cronjob|specialpage)\.php$ - [F,NC]

SWIFT 2 - alamofire - 解析JSON参数

1 个答案: