我已经做了很多搜索,找到了类似于我的问题的解决方案但到目前为止没有任何工作。任何帮助表示赞赏。
我正在尝试根据我从数据库查询的数据创建Google Line Chart,然后解析为JSON。我的查询和JSON看起来不错,但当我将其插入DataTable时,网页是空白的。
这是我的JSON输出:
[["date","percentage"],["0000-00-00 00:00:00",28.18],["2015-01-06 06:00:01",93.65],["2015-01-07 06:00:01",85.9],["2015-01-08 06:08:43",89.25],["2015-01-09 06:08:42",99.26],["2015-01-10 14:50:37",99.48],["2015-02-06 06:00:01",93.88],["2015-02-07 06:00:01",89.15],["2015-02-08 06:08:51",89.55],["2015-02-09 06:09:25",98.94],["2015-02-09 17:26:50",98.94],["2015-02-10 06:10:55",99.06],["2015-03-07 06:11:32",85.7],["2015-03-08 06:07:58",89.86],["2015-03-10 06:11:04",99.06],["2015-04-06 14:19:26",82.17],["2015-04-07 06:11:47",85.8],["2015-04-08 06:10:01",89.76],["2015-04-10 06:10:53",100],["2015-05-06 16:25:01",91.21],["2015-05-07 06:11:12",85.7],["2015-05-08 06:08:53",89.25],["2015-05-09 22:35:40",97.77],["2015-05-10 06:10:39",99.17],["2015-05-10 21:28:01",98.85],["2015-06-06 06:00:02",90.84],["2015-06-07 06:11:05",85.9],["2015-06-09 06:09:32",97.88],["2015-06-10 06:10:55",99.79],["2015-07-06 06:00:01",91.33],["2015-07-07 06:10:35",85.09],["2015-07-08 06:09:36",89.45],["2015-07-09 06:08:55",98.2],["2015-07-10 06:12:44",5.94],["2015-08-06 06:00:01",91.58],["2015-08-08 06:09:03",89.05],["2015-08-09 06:09:23",97.03],["2015-08-09 15:54:27",97.67],["2015-09-06 06:00:01",90.96],["2015-09-07 06:12:33",84.99],["2015-09-08 06:08:54",89.15],["2015-09-09 06:12:48",99.26],["2015-09-09 14:29:39",95.02],["2015-10-06 06:00:01",91.09],["2015-10-07 06:13:13",89.35],["2015-10-08 06:08:42",89.25],["2015-10-09 06:09:40",99.47],["2015-10-09 17:14:20",99.47],["2015-11-05 06:00:01",97.41],["2015-11-06 06:00:01",85.47],["2015-11-07 06:12:17",89.45],["2015-11-08 06:10:45",89.45],["2015-12-05 06:00:01",96.7],["2015-12-06 06:00:01",90.72],["2015-12-07 06:12:22",88.74],["2015-12-09 06:09:39",99.58]]
当我在https://jsonformatter.curiousconcept.com将其插入JSON Validator时,它表示它是有效的JSON,当我在所有内容中进行硬编码时似乎都有效..
这是我的代码:
<?php
$dbhost="localhost";
$dblogin="root";
$dbpwd="password!";
$dbname="qaDB";
$db = mysql_connect($dbhost,$dblogin,$dbpwd);
mysql_select_db($dbname);
$SQLString = "SELECT date, percentage FROM reports WHERE RTYPE_ID=1";
$result = mysql_query($SQLString);
$num = mysql_num_rows($result);
# set heading
$data[0] = array('date','percentage');
for ($i=1; $i<($num+1); $i++)
{
$data[$i] = array(substr(mysql_result($result, $i-1, "date"), 0, 20),
(float) mysql_result($result, $i-1, "percentage"));
}
echo json_encode($data);
mysql_close($db);
?>
以下是创建Google折线图的页面。
<html>
<head>
<title>JSON Chart Test</title>
<!-- Load jQuery -->
<script language="javascript" type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js">
</script>
<!-- Load Google JSAPI -->
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", { packages: ["corechart"] });
google.setOnLoadCallback(drawChart);
function drawChart() {
// var newWin = window.open();
var jsonData = $.ajax({
url: "legacyDashboardJSON.php",
dataType: "json",
async: false
}).responseText;
//var newStr = jsonData.substring(1, jsonData .length-1);
//newWin.document.write(jsonData);
// var parsedData = JSON.parse(newStr);
//var obj = JSON.stringify(newStr);
var data = google.visualization.DataTable(jsonData);
var options = {
title: 'Stats'
};
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data, options);
}
</script>
</head>
<body>
<div id="chart_div">
</div>
</body>
</html>
谢谢!
答案 0 :(得分:2)
更新找到解决方案。
以下是代码:
<?php
$DB_NAME = 'qaDB';
$DB_HOST = 'localhost';
$DB_USER = 'root';
$DB_PASS = '!';
$mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$result = $mysqli->query('SELECT date,percentage FROM reports');
$rows = array();
$table = array();
$table['cols'] = array(
array('label' => 'date', 'type' => 'string'),
array('label' => 'percentage', 'type' => 'number')
);
foreach($result as $r) {
$temp = array();
$temp[] = array('v' => (string) $r['date']);
$temp[] = array('v' => (int) $r['percentage']);
$rows[] = array('c' => $temp);
}
$table['rows'] = $rows;
$jsonTable = json_encode($table);
echo $jsonTable;
mysql_close($mysqli);
?>
<html>
<head>
<!--Load the Ajax API-->
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script type="text/javascript">
// Load the Visualization API and the piechart package.
google.load('visualization', '1', {'packages':['corechart']});
// Set a callback to run when the Google Visualization API is loaded.
google.setOnLoadCallback(drawChart);
function drawChart() {
var jsonData = $.ajax({
url: "legacyDashboardJSON.php",
dataType: "json",
async: false
}).responseText;
// Create our data table out of JSON data loaded from server.
var data = new google.visualization.DataTable(jsonData);
var options = {
title: 'Metrics',
width: 800,
height: 600
};
// Instantiate and draw our chart, passing in some options.
// Do not forget to check your div ID
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data, options);
}
</script>
</head>
<body>
<!--this is the div that will hold the pie chart-->
<div id="chart_div"></div>
</body>
</html>
答案 1 :(得分:0)
您需要在.ajax调用中提供一个成功函数,该函数将在数据返回时执行。任何需要数据的东西都应该放在这个函数中,或者从success函数中传递给另一个函数。您也可以在.ajax调用结束时使用.done(),并将其余的脚本放在那里。