Unix：Filter＆amp;以CSV格式处理列数据

Question

在Unix中，我如何转换CSV文件：

"0.4542703549","PRO000029D00QWERT","1.562"
"0.1585242685","PRO000030K00QWERT","4.833"
"0.4542703549","PRO000031K00QWERT","0.011"
"0.8917651385","PRO000032K00QWERT","3.057"

要：

"29","0.4542703549","1.562"
"30","0.1585242685","4.833"
"31","0.4542703549","0.011"
"32","0.8917651385","3.057"

本质上，我想从第二列（数字1-9除外）中删除所有内容，然后交换第1列和第1列的位置。 2.

提前感谢您的帮助..

Answer 1

最简单的用sed

sed 's/\("[^"]*"\),"PRO0*\([0-9]\{1,\}\)[^"]*"/\"\2",\1/' YourFile

替代

awk -F ',' -v 'quote="' '{print quote substr($2,5,6) + 0 quote "," $1 "," $3 }' YourFile