Question

我想将json对象复制到javascript数组，

{
"profiledata1":{"id":0,"music":0,"image_x":130,"image_y":155,"mouth_x":0,"mouth_y":-28.125,"active":true,"default":false},
"profiledata2":{"id":1,"music":0,"image_x":130,"image_y":155,"mouth_x":0,"mouth_y":0,"active":true,"default":false},
"profiledata3":{"id":2,"music":0,"image_x":0,"image_y":0,"mouth_x":0,"mouth_y":0,"active":false,"default":false},
"profiledata4":{"id":3,"music":0,"image_x":0,"image_y":0,"mouth_x":0,"mouth_y":0,"active":false,"default":false},
"profiledata5":{"id":4,"music":0,"image_x":0,"image_y":0,"mouth_x":0,"mouth_y":0,"active":false,"default":false},
"upload":"http:\/\/localshost\/",
"format":"jpeg","status":1 }

这是我通过ajax调用some.php时返回的json对象，我想在java脚本中将profiledata1复制到userdata_arr [0]，将profiledata2复制到userdata_arr [1]，将profiledata3复制到userdata_arr [2]，将profile4data复制到userdata_arr [3]，将profiledata5复制到userdata_arr [5]。我的java脚本如下，

$.ajax({
    type: "POST",
    url: "some.php",
    data: {action:'load',
            id:7}

}).done(function(o) {
    var data = $.parseJSON(o);
    if (!data || data === null) {
        someError(true);

    }else{ 
        if(data.status==true){
            userdata_arr[0] = data.profiledata1[0];
            userdata_arr[1] = data.profiledata2[0];
            userdata_arr[2] = data.profiledata3[0];
            userdata_arr[3] = data.profiledata4[0];
            userdata_arr[4] = data.profiledata5[0];
            uploadDir = data.upload;
            imgFormat = data.format;


            somefunction();
        }else{
            someError(true);
        }
    }
});

当我执行此脚本时，我将userdata_arr视为未定义！请帮我纠正这个问题。我也在这里附上some.php，

<?php
if ($_POST['action']=='load') {
$uid=$_POST['id'];

header("content-type:application/json");
// fetch contents from db with $uid;
$query = mysqli_query($link,$sql);
while ($row = mysqli_fetch_array($query)) {
    $prof1 = $row['prof1'];
    $prof2 = $row['prof2'];
    $prof3 = $row['prof3'];
    $prof4 = $row['prof4'];
    $prof5 = $row['prof5'];
}
$jp1 = json_decode($prof1, 1);
$jp2 = json_decode($prof2, 1);
$jp3 = json_decode($prof3, 1);
$jp4 = json_decode($prof4, 1);
$jp5 = json_decode($prof5, 1);

echo json_encode($dta = array('profile1data' =>json_decode($prof1),'profile2data' =>json_decode($prof2),'profile3data' =>json_decode($prof3),'profile4data' =>json_decode($prof4),'profile5data' =>json_decode($prof5) ,'upload' =>'http://localhost/img/', 'format' =>'jpeg', 'status' =>1 )); ?>

提前致谢！

Answer 1

那是因为你还没有宣布你的userdata_arr。要修复它，请在使用之前声明您的数组/对象变量。在else代码块中，执行以下操作：

else{ 

    var userdata_arr = {}// declare your object

    if(data.status==true){ //proceed to use your already-declared object, also notice the quote marks surrounding the object members/indexes
        userdata_arr["0"] = data.profiledata1[0];
        userdata_arr["1"] = data.profiledata2[0];
        userdata_arr["2"] = data.profiledata3[0];
        userdata_arr["3"] = data.profiledata4[0];
        userdata_arr["4"] = data.profiledata5[0];
        uploadDir = data.upload;
        imgFormat = data.format;


        somefunction();
    }else{
        someError(true);
    }
}

将json对象复制到javascript数组

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