Question

我已经在我的数据库查询上构建了一个过滤器我想让它更舒服。目标是使其具有动态意味着用户可以选择尽可能多地组合。

public function filter(FilterList $request)
{
    $view = view('profile.browse.list');
    $search = $request->get('filter');

    $filter = [
            'male'   => Profile::male(),
            'female' => Profile::female(),
            '10'     => Profile::man(),
            '11'     => Profile::women(),
            '12'     => Profile::couple(),
            '15'     => Profile::domina(),
            '20'     => Profile::affaire(),
            '21'     => Profile::cybersex(),
            '22'     => Profile::marriage(),
            '23'     => Profile::flirt(),
    ];

    return $view->with([
        'List' => $filter[$search]->unmoderated()->paginate(15)->appends(['filter' => $search]),
    ]);

}

我知道我的解决方案并不是一个好的解决方案。我已将查询范围保存在$ filter数组中无法添加像这样的第二个或所需的范围

$users = User::popular()->women()->orderBy('created_at')->get();

http://laravel.com/docs/5.0/eloquent#query-scopes

为了让它变得更好，我有任何暗示。

我不知道要开始......

感谢您的帮助

修改

public function scopeMarriage($query)
{
 return $query->where('LookFor', 'LIKE', '%Ehe%');
}

Answer 1

因此，用户正在提交动态数量的输入，并且根据这些输入，您希望将查询范围链接到查询中？如果这就是你想要的，我相信你可以这样做：

// Method array taken from your example
$methods = [
    'male'    => 'male',
    'female'  => 'female',
    '12'      => 'couple',
];

// Begin the query. Since the unmoderated() scope query is always called,
// I used that in this example.
// But note that you can also use Model::query(); to begin a query
$query = Profile::unmoderated();

// Loop through the request inputs
foreach ($request->all() as $param)
{
    // If it exists in the provided array, add it to the query.
    if (array_key_exists($param, $methods))
    {
        $query->{$methods[$param]}();
    }
}

// Call get, paginate, etc. to actually fetch the results and then return it.
return $query->paginate(15);

多个动态查询范围

1 个答案: