我Fragment
内有AsyncTask
Activity
。但是当我运行搜索时,我得到了这个例外:
Attempt to invoke virtual method 'android.content.res.Resources$Theme android.content.Context.getTheme()' on a null object reference.
它与Fragment有关,不知道Activity是否正在运行,但我不知道如何修复它。 请帮忙。 这是代码:
class Send_API extends AsyncTask<String, Void, String> {
private ProgressDialog dialog;
@Override
protected void onPreExecute() {
if (movieList != null){
movieList.clear();
adapter.notifyDataSetChanged();
}
dialog = new ProgressDialog(getActivity());
dialog.setMessage("Searching...");
dialog.show();
}
@Override
protected String doInBackground(String... params) {
String queryString = null;
try {
queryString = "" +
"s=" + URLEncoder.encode(txt, "utf-8");
} catch (UnsupportedEncodingException e) {
}
return HttpHandler.get(params[0], queryString);
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
dialog.dismiss();
if (result == null) {
Toast.makeText(getActivity(), "error getting results...", Toast.LENGTH_LONG).show();
} else {
try {
JSONObject json = new JSONObject(result);
JSONArray searchArray = json.getJSONArray("Search");
for (int i = 0; i < searchArray.length(); i++) {
JSONObject searchObject = searchArray.getJSONObject(i);
String title = searchObject.getString("Title");
String type = searchObject.getString("Type");
String year = searchObject.getString("Year");
String imdbID = searchObject.getString("imdbID");
String poster_url = searchObject.getString("Poster");
movieList.add(new Movie(title, type, year, imdbID, poster_url));
Log.e(TAG, "MovieList is " + movieList);
}
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getActivity(), "error parsing results...", Toast.LENGTH_LONG).show();
}
adapter.notifyDataSetChanged();
}
}
}
答案 0 :(得分:0)
dialog = new ProgressDialog(getActivity());
初始化getActivity()
时, Fragment
将返回null。您必须等到片段生命周期中的onAttach()
才能返回非空。
这就是NPE
。
总的来说,片段中没有非默认构造函数。仅在onCreateView()
。
答案 1 :(得分:0)
尝试将基本上下文传递给您的asynctask并将outer_dictionary = your_list[0]
list_of_dictionaries = outer_dictionary['tr']
替换为names = []
for dictionary in list_of_dictionaries:
if "name" in dictionary:
names.append(dictionary["name"])