Question

我现有的查询是：

SELECT @str = coalesce(@str + ']' + ', ', '') + '[' + monthyear
FROM (SELECT DISTINCT ( monthyear), ExpectedDate
      FROM table) s
order by ExpectedDate

我需要按日期

按顺序添加唯一的monthyear字符串

ExpectedDate    monthyear
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-11-01       Nov-15
2015-12-01       Dec-15
2015-12-01       Dec-15
2015-12-01       Dec-15
2015-12-01       Dec-15
2015-12-01       Dec-15
2015-12-01       Dec-15
2015-12-01       Dec-15
2015-12-01       Dec-15
2015-12-02       Dec-15
2015-12-30       Dec-15
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-01       Jan-16
2016-01-04       Jan-16
2016-01-04       Jan-16
2016-01-04       Jan-16
2016-01-04       Jan-16
2016-02-01       Feb-16
2016-02-01       Feb-16
2016-02-01       Feb-16
2016-02-01       Feb-16
2016-02-01       Feb-16
2016-02-01       Feb-16
2016-02-01       Feb-16
2016-02-01       Feb-16
2016-02-01       Feb-16
2016-03-01       Mar-16
2016-03-01       Mar-16
2016-03-01       Mar-16
2016-03-01       Mar-16
2016-03-01       Mar-16
2016-03-01       Mar-16
2016-03-01       Mar-16
2016-04-01       Apr-16
2016-04-01       Apr-16
2016-04-01       Apr-16
2016-04-01       Apr-16
2016-04-01       Apr-16
2016-06-01       Jun-16
2016-06-01       Jun-16
2016-07-01       Jul-16
2016-10-01       Oct-16
2016-10-01       Oct-16
2016-12-01       Dec-16
2016-12-30       Dec-16

Answer 1

使用XML PATH

DECLARE @t table(ExpectedDate date, monthdate char(8))
INSERT @t values
('2015-11-01', 'Nov-2015'),
('2015-11-01', 'Nov-2015'),
('2015-12-01', 'Dec-2015'),
('2015-12-01', 'Dec-2015'),
('2016-01-01', 'Jan-2016')

SELECT 
    STUFF(( 
        SELECT ',[' + STUFF(monthdate,4,1, '') + ']'
        FROM @t t1 
        GROUP BY ExpectedDate, monthdate
        ORDER BY ExpectedDate
        for xml path(''), type 
    ).value('.', 'varchar(max)'), 1, 1, '') [values]

结果：

[Nov2015],[Dec2015],[Jan2016]

Answer 2

尝试使用我MonthName()提供的Year()和MySQL内置函数。

MonthName(ExpectedDate), Year(ExpectedDate)

Ex：Month(2016-02-01)给你Februray

然后你可以结果。

Answer 3

如果monthyear列为varchar类型，您可以尝试：

SELECT '[' + SUBSTRING(monthyear, 1, 3) + CAST(YEAR(PAY_DATE) AS VARCHAR) + ']'
FROM Your_Table

如果monthyear列为date或datetime，请尝试以下操作：

SELECT '[' + SUBSTRING(DateName(month, DateAdd(month, MONTH(Pay_Date), 0) - 1 ), 1, 3)
           + CAST(YEAR(PAY_DATE) AS VARCHAR) + ']'
FROM Your_Table

按日期顺序创建月份字符串

3 个答案: