Question

你好，我写了一些从网站上获取XML的PHP，并将它存储在我数据库的表中。它呼应成功，但表格是空白的吗？继承我的代码：

<?php

$url ="http://rates.fxcm.com/RatesXML3";
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url);

$data = curl_exec ($ch);
curl_close($ch);

$xml = simplexml_load_string($data);

$con = mysql_connect("localhost","username","password"); //this does contain proper information, just ive hidden it with the following
mysql_select_db("database", $con) or die(mysql_error()); //same for database too

foreach ($xml -> Rate as $row){
    $Symbol = $row -> Symbol;
    $Bid = $row -> Bid;
    $Ask = $row -> Ask;

//performing sql query

$sql = "INSERT INTO 'FXCM_Rates' ('Symbol', 'Bid', 'Ask')"  
            . "VALUES ('$Symbol', '$Bid', '$Ask')";

$result = mysql_query($sql);
if (!result) {
    echo 'MySQL ERROR';
    } else{
    echo 'SUCCESS';
}
}

＆GT;

现在，当我检查PHP时，它已经成功回归所有63种费率，但是当我去检查表时，它是空白的？我觉得奇怪的是，它对其他人都有效，但不是我:(

感谢任何有助于修复我的代码的人/指出我的错误。

Answer 1

你有＆＃39; $＆＃39;最后失踪了。

  if (!$result) {

现在我已经完成了一些测试，你的变量是我不确定你可以像这样插入数据库的对象。

foreach ($xml -> Rate as $row){
 $Symbol = (string)$row -> Symbol;
 $Bid    = (string)$row -> Bid;
 $Ask    = (string)$row -> Ask;
}

这将返回可能更易于查询的字符串

Answer 2

在较新版本的php中不推荐使用mysql，你应该使用mysqli（改进版）..

<?php

$url ="http://rates.fxcm.com/RatesXML3";
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url);

$data = curl_exec ($ch);
curl_close($ch);

$xml = simplexml_load_string($data);

$con = mysqli_connect("localhost","username","password","database") or die(mysqli_error($con));

foreach ($xml -> Rate as $row){
    $Symbol = $row -> Symbol;
    $Bid = $row -> Bid;
    $Ask = $row -> Ask;

//performing sql query

$sql = "INSERT INTO 'FXCM_Rates' ('Symbol', 'Bid', 'Ask')"  
            . "VALUES ('$Symbol', '$Bid', '$Ask')";

$result = mysqli_query($con,$sql);
if (!$result) {
    echo 'MySQL ERROR';
    } else{
    echo 'SUCCESS';
}
}

为什么我的桌子保持空白，即使它回声成功？

2 个答案: