Question

我想做简单但需要以最快的方式在javascript中执行此操作：

我有这个数组：

   players: [{
       isInjured : false,
       name: ... 
       stamina : 50
   },{
       isInjured : true,
       name: ...,
       stamina : 20
   }
   ...
]

我想以最好，最快的方式做两件事：

1）如果我在数组中的“inInjured”属性中为true，则为任何人。

2）我想提取3个最低耐力的球员，并提取其中一个的关键。

如果可能的话，我想避免为此做2 forEach，那么最好的方法是什么？

Answer 1

＆＃13;

var players = [{
  isInjured: false,
  stamina: 50
}, {
  isInjured: false,
  stamina: 10
}, {
  isInjured: false,
  stamina: 15
}, {
  isInjured: false,
  stamina: 16
}, {
  isInjured: true,
  stamina: 20
}];



// Your second request you can do with lodash or underscore easily

var threePlayersWithMinStamina = _.take(_.sortBy(players, function(player) {
  return player.stamina;
}), 3);

console.log(threePlayersWithMinStamina) // you have the three players with the min stamina

//Your first request
// the var isOneInjured will be true if the condition will be true and stop the loop
var isOneInjured = players.some(function(player) {
  return player.isInjured;
});

＆＃13;

<script src="https://cdn.rawgit.com/lodash/lodash/3.0.1/lodash.min.js"></script>

＆＃13;

Answer 2

使用数组本机some函数，如下文

var isSomeoneInjurd = players.some(function(pl){
    return pl.isInjured;
});

如果任何玩家的财产isSomeoneInjurd为真，则isInjured的值为true。一旦它获得该属性的真实，它就会打破循环。

找到对象是否具有某种属性和真理的最快方法？

2 个答案: