Question

我有以下服务器端代码： -

item[@"Month"]

一旦我尝试使用以下内容调用此选项，我收到415错误。能告诉我解决这个问题的方法吗？

    import org.json.JSONObject;
    @Path("/user")
    public class Users {

    @POST
    @Path("register")
    @Produces(MediaType.APPLICATION_JSON)
    @Consumes(MediaType.APPLICATION_JSON)
    public Response registerUser(JSONObject userDetails) {
        return Response.status(Status.ACCEPTED).entity("User Created.Details are: " + userDetails).build();
    }
}

顺便说一句，我正在使用泽西岛。

Answer 1

在JAX-RS中，您必须创建一个MessageBodyReader readFrom并返回InputStream的JSON JSONObject。

@Provider
@Consumes(MediaType.APPLICATION_JSON)
public class JSONObjectMessageBodyReader implements MessageBodyReader<JSONObject> {

    public boolean isReadable(Class<?> type, Type genericType, Annotation[] annotations, MediaType mediaType) {
        return true;
    }

    public JSONObject readFrom(Class<T> type, Type genericType, Annotation[] annotations, MediaType mediaType, MultivaluedMap<String, String> httpHeaders, InputStream entityStream) throws java.io.IOException, javax.ws.rs.WebApplicationException {
        //Using entityStream, read the content and return a  JSONObject back...
        BufferedReader streamReader = new BufferedReader(new InputStreamReader(entityStream, "UTF-8")); 
        StringBuilder responseStrBuilder = new StringBuilder();

        String inputStr;
        while ((inputStr = streamReader.readLine()) != null)
            responseStrBuilder.append(inputStr);

        return new JSONObject(responseStrBuilder.toString());
    }
}

Answer 2

一种简单的方法是 -

public void parseJson(WebResource service) throws UniformInterfaceException, JSONException {

  JSONArray resultArray = new JSONArray(service.path("resources/test/json/Tom").get(String.class));

  List<User> userList = new ArrayList<User>();

  for (int count = 0; count < resultArray.length(); count++) {

    JSONObject userObject = resultArray.getJSONObject(count);
    // this is tor read a sample JSON., this code will change according to your need.
    User user = new User(userObject.get("name").toString(), userObject.get("surname").toString(), userObject.get("address").toString()); 

    userList.add(user);

  }

  System.out.println(userList);

 }

此代码专门针对Jersey Web服务编写。

请在泽西岛找到更多编码链接 -

Creating Webservices with Maven and Jersy

编辑:(客户端需要在其类路径中使用java-json.jar来开发此代码）。

将Json传递给Rest并通过JSONObject接收它

2 个答案: