Question

我希望在下面的方法中，基于 attrNameListCurrent.Length ， else if else 代码块。换句话说，如果 attrNameListCurrent.Length = 2 我只需要（attrNameListCurrent [0]！= attrNameListPrevious [0]）和

＆＃xA; ＆＃XA;

 <代码>否则＆＃XA; {＆＃XA; result + = AddItem（attrList [i]）;＆＃xA; if（i == attrList.Count  -  1）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; result + = CloseObject（attrList [i]）; ///＆＃XA; }＆＃xA;

＆＃xA;＆＃xA;

代码的一部分。

＆＃xA;＆＃xA;

如果 attrNameListCurrent.Length = 3 我想添加 else if（attrNameListCurrent [1]！= attrNameListPrevious [1]）它们之间的代码块

＆＃xA;＆＃xA;

if attrNameListCurrent.Length = 4 我想添加 else if（attrNameListCurrent [2]！= attrNameListPrevious [2]）代码块等等。

＆＃xA;＆＃xA;

有没有办法以编程方式执行此操作？请提出任何建议。＆＃xA;我的方法：

＆＃xA;＆＃xA;

 公共静态字符串ReadRsdToJson（List＆lt; AttributeProperties＆gt; attrList）＆＃xA; {＆＃XA; string result =“{”;＆＃xA; bool createNew = true;＆＃xA; string attrName = string.Empty;＆＃xA; string [] attrNameListCurrent;＆＃xA; string [] attrNameListPrevious; ＆＃XA; if（attrList.Count == 0）result =“{}”; //测试-1;列表是空的＆＃xA; for（var i = 0; i＆lt; attrList.Count; i ++）＆＃xA; {＆＃XA; if（attrList [i] .XPath！= null）＆＃xA; {＆＃XA; if（i == 0）result + = CreateNewObject（attrList [i]）;＆＃xA; if（i == 0＆amp;＆amp; i == attrList.Count  -  1）result + = CloseObject（attrList [i]）;＆＃xA;＆＃xA; attrNameListCurrent = attrList [i] .XPath.Split（'/'）;＆＃xA; if（i！= 0）＆＃xA; {＆＃XA; attrNameListPrevious = attrList [i  -  1] .XPath.Split（'/'）; ＆＃XA; if（attrNameListCurrent [0]！= attrNameListPrevious [0]）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）; //关闭上一个对象＆＃xA; if（attrNameListCurrent [0]！= attrList [i-1] .XPath.Split（'/'）[0]）result + = CloseObject（attrList [i-1]）; //创建新对象＆＃xA; result + = CreateNewObject（attrList [i]）;＆＃xA; if（i == attrList.Count-1）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; result + = CloseObject（attrList [i]）; ///＆＃XA; ＆＃xA; }＆＃XA; else if（attrNameListCurrent [1]！= attrNameListPrevious [1]）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; if（attrNameListCurrent [1]！= attrList [i  -  1] .XPath.Split（'/'）[1]）result + = CloseNestedNthObject（attrList [i-1]，1）;＆＃xA; result + = CreateNestedNthElement（attrList [i]，1）;＆＃xA; if（i == attrList.Count  -  1）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; result + = CloseObject（attrList [i]）;＆＃xA; ＆＃xA; }＆＃XA; else if（attrNameListCurrent [2]！= attrNameListPrevious [2]）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; if（attrNameListCurrent [2]！= attrList [i  -  1] .XPath.Split（'/'）[2]）result + = CloseNestedNthObject（attrList [i-1]，2）;＆＃xA; result + = CreateNestedNthElement（attrList [i]，2）;＆＃xA; if（i == attrList.Count  -  1）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; result + = CloseObject（attrList [i]）;＆＃xA; ＆＃xA; }＆＃XA; else if（attrNameListCurrent [3]！= attrNameListPrevious [3]）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; if（attrNameListCurrent [3]！= attrList [i  -  1] .XPath.Split（'/'）[3]）result + = CloseNestedNthObject（attrList [i-1]，3）;＆＃xA; result + = CreateNestedNthElement（attrList [i]，3）;＆＃xA; if（i == attrList.Count  -  1）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; result + = CloseObject（attrList [i]）;＆＃xA; ＆＃xA; }＆＃XA;否则＆＃XA; {＆＃XA; result + = AddItem（attrList [i]）;＆＃xA; if（i == attrList.Count  -  1）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA; result + = CloseObject（attrList [i]）; ///＆＃XA; ＆＃xA; }＆＃XA; ＆＃xA; }＆＃XA;否则＆＃XA; {＆＃XA; if（attrList [i] .Type ==“integer”|| attrList [i] .Aggregate！= null）＆＃xA; {＆＃XA;结果+ ='“'+ attrList [i] .Name +'”'+“：”+ attrList [i] .Value +'，';＆＃xA; }＆＃XA;否则＆＃XA; {＆＃XA;结果+ ='“'+ attrList [i] .Name +'”'+“：”+'“'+ attrList [i] .Value +'”'+'，';＆＃xA; }＆＃XA; }＆＃XA; if（i == attrList.Count  -  1）＆＃xA; {＆＃XA; result = result.TrimEnd（'，'）;＆＃xA;结果+ ='}';＆＃xA; }＆＃XA; }＆＃XA;返回结果;＆＃xA; }＆＃XA;

＆＃XA;

Answer 1

你有没有关于使用switch语句？如果我理解正确的话，听起来可能就是你所需要的。

像

这样的东西

switch (attrNameListCurrent.Length)
        {
            case 1:
                #if length is 1 do thing
                break;
            case 2:
                #if length is 2 do thing
                break;
            case 3:
                #if length is 3 do thing
                break;
        }

Answer 2

如果您要做的是从路径+值列表构建树，然后将其序列化为JSON，则构建树然后序列化将更容易。假设您有一个TreeNode类，其中存储了子TreeNodes和Value的列表。假设它支持索引器，因此您可以使用[]访问子节点。然后你可以做这样的事情：

public static string ReadRsdToJson(List<AttributeProperties> attrList)
{
  var root = new TreeNode();
  foreach (var attr in attrList)
  {
     var pathElements = attr.XPath.Split('/');
     var current = root;

     // Scan down the path following or building the tree at each step

     foreach (var pathElement in pathElements)
     {
        if (current.ContainsKey(pathElement))
          current = current[pathElement];
        else
        {
           var newChild = new TreeNode(pathElement);
           current.AddChild(newChild);
           current = newChild;
        }
     }

     // current is now the node at leaf of the tree that you want
     current.Value = attr.Value;
  }

  // And now you have built a tree you can serialize that to Json
  // If you must write your own serializer instead of using JSON.NET
  // consider using string.Join(",",...) instead of trimming commas
}

它与您的代码完全不符，但对于SO问题，您的代码实际上太长且太复杂了。最好将其简化为您所要求的本质。

在c＃中动态定义方法

2 个答案: