Question

这是我的代码，我试图找到字符串vowelCount和keepng轨道中有多少元音在int count [];所以字符串是（“black banana republic boots”），输出应该是{4,1,1,2,1}。我的数学是否正确。如果不是什么错误

class lab204 {

    public static String vowelCount() {
        String vowelCount[] = ("black banana republic boots"); 
        int count[];
        int counter = 0;
        for( int i=0; i<s.length(); i++ ) {
        if( vowelCount.charAt(i) == 'a' ) {
            counter++;
        } 
        if( vowelCount.charAt(i) == 'e' ) {
         counter++;
        } 
        if( vowelCount.charAt(i) == 'i' ) {
            counter++;
        } 
        if( vowelCount.charAt(i) == 'o' ) {
            counter++;
        } 
        if( vowelCount.charAt(i) == 'u' ) {
         counter++;
        } 
    }

  }
}

Answer 1

首先，您的代码将无法编译。这是因为您正在错误地创建数组。请注意，您不需要数组，除非您想一次计算多个字符串。

public static String vowelCount() {

    //Does not need to be an array
    String sentence = "black banana republic boots";

    //Create your array to count 5 vowels
    int[] vowelCount = { 0, 0, 0, 0, 0 };

    for( int i = 0; i < sentence.length(); i++ ) {

        //Don't forget to check for uppercase too!
        if( sentence.charAt(i) == 'a' || sentence.charAt(i) == 'A' ) {
            vowelCount[0]++;
        } 
        if( sentence.charAt(i) == 'e' || sentence.charAt(i) == 'E' ) {
            vowelCount[1]++;
        } 
        if( sentence.charAt(i) == 'i' || sentence.charAt(i) == 'I' ) {
            vowelCount[2]++;
        } 
        if( sentence.charAt(i) == 'o' || sentence.charAt(i) == 'O' ) {
            vowelCount[3]++;
        } 
        if( sentence.charAt(i) == 'u' || sentence.charAt(i) == 'U' ) {
            vowelCount[4]++;
        } 
    }
}

我假设你对数组知之甚少，所以我建议你阅读here。

此外，您的函数被声明为返回一个字符串，当您真的想要返回带有元音数的数组时。像这样改变你的函数声明：

public static int[] vowelCount() {

在函数结束时，在for循环之后，返回vowelCount数组：

public static int[] vowelCount() {
    String sentence = "black banana republic boots";
    int[] vowelCount = { 0, 0, 0, 0, 0 };

    for (int i = 0; i < sentence.length(); i++) {
        //If statements
        //...
    } //End of for loop

    //Return the array counting the vowels
    return vowelCount;
} //End of function

Answer 2

请填写空白

public static String vowelCount() {
    String s = ("black banana republic boots"); //test string
    int count[] = new int[__]; //to use an int array for counting

    for( int i=0; i<s.length(); i++ ) { //looking at test string, one char at a time
    if( s.charAt(i) == 'a' ) {
        count[0]++; //increment the first array element
    } 
    if( s.charAt(i) == 'e' ) {
     ___________ //increment the second array element
    } 
    if( s.charAt(i) == 'i' ) {
       ___________ //...
    } 
    if( s.charAt(i) == 'o' ) {
        __________ //...
    } 
    if( s.charAt(i) == 'u' ) {
     _____________
    } 
  }

}

Answer 3

有些观点：

1）如果有其他行，则不需要{}括号

2）以下是您的情况的示例代码

public class VowelTester {

char[] vowels = {'a','e','i','o','u'};



/** Check for vowels 
 * @param sample
 * @return array containing the counter of each vowel [a,e,i,o,u]
 */
public int[] checkForVowels(String sample) {
    int[] array = new int[5];

    for (int i = 0; i < sample.length(); i++) {
        if (sample.charAt(i) == 'a')
            array[0] += 1;

        if (sample.charAt(i) == 'e')
            array[1] += 1;

        if (sample.charAt(i) == 'i')
            array[2] += 1;

        if (sample.charAt(i) == 'o')
            array[3] += 1;

        if (sample.charAt(i) == 'u')
            array[4] += 1;

    }

    System.out.println("a:"+array[0]+" e:"+array[1]+" i:"+array[2]+" o:"+array[3]+" u:"+array[4]);

    return array;
}


  public static void main(String[] args){
    new VowelTester().checkForVowels("Find out how many vowels i have");
  }
}

找出字符串中有多少个元音

3 个答案: