Question

我正在使用aryaxt/iOS-Slide-Menu。我的问题是：我需要显示不同的左菜单，具体取决于显示哪个View Controller。这是我在AppDelegate中的代码：

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
    // Override point for customization after application launch.
 UserMenuViewController *leftMenu = (UserMenuViewController *) [self.window.rootViewController.storyboard instantiateViewControllerWithIdentifier:@"UserMenuViewController"];


    [SlideNavigationController sharedInstance].leftMenu = leftMenu;

当我尝试在我的特殊ViewController中更改左侧菜单时，左侧菜单中出现黑屏。

AppDelegate *sharedeDelegate = ((AppDelegate *)[UIApplication sharedApplication].delegate);

    ProfessionalMenuViewController *leftMenu = (ProfessionalMenuViewController *) [sharedeDelegate.window.rootViewController.storyboard instantiateViewControllerWithIdentifier:@"ProfessionalMenuViewController"];
    [SlideNavigationController sharedInstance].leftMenu = leftMenu;

我尝试了很多东西，但没有任何效果。谢谢！

Answer 1

我只知道一个解决方案：

 AppDelegate *delegate = (AppDelegate *)[UIApplication sharedApplication].delegate;
UIStoryboard *mainStoryboard = [UIStoryboard storyboardWithName:@"Main" bundle: nil];

SlideNavigationController* landingScreen = (SlideNavigationController*)[mainStoryboard
                                                  instantiateViewControllerWithIdentifier: @"SlideNavigationController"];
LeftMenuViewController *leftMenu = (LeftMenuViewController*)[mainStoryboard instantiateViewControllerWithIdentifier: @"CVLeftMenuViewController"];

landingScreen.leftMenu = leftMenu;
landingScreen.enableShadow=YES;
landingScreen.enableSwipeGesture = YES;
landingScreen.panGestureSideOffset = 0;

delegate.window.rootViewController = landingScreen;

需要更新SlideNavigationController请参阅landingScreen（我在更改语言时使用，无需重新启动应用程序）

Answer 2

我建议自定义leftMenuViewController，设置一个全局变量，并根据全局变量的值在左侧菜单中显示不同的tableview内容，或者在leftMenuViewController中处理SlideNavigationControllerDidReveal通知，并根据当前打开的侧视图控制器添加任何子视图或删除子视图。

iOS-Slide-Menu中的不同ViewControllers

2 个答案: