尝试编写一个函数,通过修改线性搜索函数来查找向量中目标的最后一次出现...
<module id="javax.persistence" javadoc="http://java.sun.com/javaee/5/docs/api"/>
我想到了一种通过使用辅助函数使其工作的方法......
private int linearSearchRecursive(int[] input, int key,int index) {
if (index == 0) {
return -1;
}
if (input[index] == key) {
return index;
}
else
return linearSearchRecursive(input,key,--index);
}
或者那种性质的东西,但是想知道是否有一种更简单的方法,我只能使用一个函数但保持递归?
答案 0 :(得分:2)
不容易但只有一个功能:
public class Test {
public static int findLastOccuranceRecursive(int[] input, int key, int... optionalIndex) {
if (optionalIndex.length == 0) {
optionalIndex = new int[] { input.length - 1 };
} else if (optionalIndex.length != 1) {
throw new IllegalArgumentException("size of optionalIndex must be 0 or 1");
}
if (optionalIndex[0] == 0) {
return -1;
}
if (input[optionalIndex[0]] == key) {
return optionalIndex[0];
} else {
optionalIndex[0]--;
return findLastOccuranceRecursive(input, key, optionalIndex);
}
}
public static int findLastOccuranceIterative(int[] items, int key) {
for (int i = items.length - 1; i >= 0; i--) {
if (items[i] == key) {
return i;
}
}
return -1;
}
public static void main(String[] args) {
int[] input = { 1, 1, 1, 2, 1, 2, 1, 1 };
int testRecursive = findLastOccuranceRecursive(input, 2);
int testIterative = findLastOccuranceIterative(input, 2);
System.out.println("testRecursive: " + testRecursive + " testIterative: " + testIterative);
}
}