Question

def poundsToMetric(pounds):
    kilograms = pounds / 2.2
    grams = kilograms * 1000
    return int(kilograms), grams % 1000

pounds = float(input("How many Pounds? "))
kg, g = poundsToMetric(pounds)
print('The amount of pounds you entered is {}. '\
      'This is {} kilograms and {} grams.'.format(pounds, kg, g))

这个程序有效，但我想知道如何让公斤只有小数点，所以而不是65磅像545.4544545454克我需要它545克

Answer 1

有两种方法：

使用 round（）内置函数

def poundsToMetric(pounds):
    kilograms = pounds / 2.2
    grams = kilograms * 1000
    return int(kilograms), grams % 1000

pounds = float(input("How many Pounds? "))
kg, g = poundsToMetric(pounds)
print('The amount of pounds you entered is {}. This is {} kilograms and {} grams.'.format(pounds, kg, round(g)))

使用 int（）强制转换来获取值的整数部分：

def poundsToMetric(pounds):
    kilograms = pounds / 2.2
    grams = kilograms * 1000
    return int(kilograms), grams % 1000

pounds = float(input("How many Pounds? "))
kg, g = poundsToMetric(pounds)
print('The amount of pounds you entered is {}. This is {} kilograms and {} grams.'.format(pounds, kg, int(g)))

分别参见以下各种方式的输出：

➜  python help.py
How many Pounds? 65
The amount of pounds you entered is 65.0. This is 29 kilograms and 545.0 grams.

➜  python help.py
How many Pounds? 65
The amount of pounds you entered is 65.0. This is 29 kilograms and 545 grams.

Answer 2

如果添加行

print type(grams%1000)

您将获得输出

<type 'float'>

所以这显然是返回一个浮点数。将其投射到int以获得所需的结果。

而不是这样做：

return int(kilograms), grams % 1000

这样做：

return int(kilograms), int(grams % 1000)

现在你的程序输出是：

The amount of pounds you entered is 65. This is 29 kilograms and 545 grams.

正是你想要的。

磅到公制python程序

2 个答案: