Question

我使用Mongoose 4.1.11

执行此错误非常困难：

console.log("step1"); // that's display every time in my console => ok

models.users.findOne({email: mail}, function (err, myUser) {
    console.log("step2"); // That's very very weird, that's work but RARELY that's doesn't work
    ...

有时，由于此问题，我的API服务器无效，

编辑＃1

所以，我将服务器托管从Gandi更改为Heroku。现在，它的作品非常好！谢谢你的帮助; - ）

Answer 1

您应该使用错误回调参数，如下所示;

models.users.findOne({email: mail}, function (err, myUser) {
    if (!err) console.log("step2"); // That's very very weird,that's work but RARELY that's doesn't work
    else console.log(err.message);
    ...

Mongo会在出现问题时生成错误对象，您可能会在此用法中出现错误原因。

Answer 2

    var User = mongoose.model('User', UserSchema);
    User.findOne({email: mail}, function (err, myUser) {
        console.log("step2"); // That's very very weird, that's work but RARELY that's doesn't work
    }

Answer 3

所以，我将服务器托管从Gandi更改为Heroku。现在，它的作品非常好！谢谢你的帮助; - ）

mongoose findOne（{email：email}）经常很少工作不起作用？

3 个答案: