这就是我所拥有的:我想制作一个程序,要求用户输入:你的名字。
这是我需要帮助的:然后,我希望程序读取名称中的每个字符,字母。最后,我希望它返回与用户名中每个字符对应的形容词列表。
这是我到目前为止所做的:
public static void main (String [] args) {
System.out.println("This program will give meanings to every "
+ "letter in your name.\n");
Scanner input = new Scanner (System.in);
System.out.println("Please enter your name:");
String name = input.next();
String A = "adventurous";
String B = "bold";
String C = "caring";
String D = "devoted";
String E = "encouraging";
String F = "funny";
String G = "gentle";
String H = "honest";
String I = "intelligent";
String J = "joyful";
String K = "kind";
String L = "loving";
String M = "mature";
String N = "neat";
String O = "organized";
String P = "persistent";
String Q = "quick";
String R = "religious";
String S = "sensitive";
String T = "thankful";
String U = "useful";
String V = "virtuous";
String W = "witty";
String X = "this letter isn't in your name";
String Y = "young";
String Z = "zany";
}
答案 0 :(得分:3)
将你的形容词放在Map中(以char作为键和形容词作为值)而不是使用这些字符串,然后将名称转换为CharArray,迭代它并为每个字母只从地图中获取项目。您可以将您的形容词放入列表中,然后再打印出来。
//create the map and the list of adjectives
Map<Character, String> adjectives = new HashMap<>();
List<String> personAdjectives = new ArrayList<>();
//fill the map (although it would be better retrieving data from a database)
adjectives.put('a',"adventurous");
adjectives.put('b',"bold");
// ...
//convert the name to a char array
char[] chars = name.toCharArray();
//iterate over it
for(char c : chars){
//access the map and fill the list
personAdjectives.add(adjectives.get(c));
}
//print the list
答案 1 :(得分:-1)
#我希望这可以帮助#
import java.io.*;
public class StringRead
{
public static void main(String[] arg){
String hi = "hi all man and sexy.";
for(int x = 0; x < hi.length(); x++){
System.out.println(hi.charAt(x));
}
}
}