Question

我想知道这是否可能......？

想象一下带有输入框小部件的tkinter应用程序，用于输入PC名称。一旦用户开始在框中键入内容，应用程序将根据您键入的内容显示可能的名称，因此您输入的选项越多，您看到的选项就越少，只留下一个或足够小的选择在可用选项上。

如果在tkinter中可以做到这一点，如果有人能指出我的方向，那就太棒了！

我无法发布任何示例代码，因为这是一般而非具体的问题。

Answer 1

您可以将StringVar的实例与条目小部件相关联，然后在该实例上设置跟踪以在值更改时调用回调。然后，您可以在回调中执行任何操作 - 更新列表，弹出窗口等等。

以下是根据您输入内容简单过滤列表的示例。

import Tkinter as tk

class Example(tk.Frame):
    def __init__(self, parent):
        tk.Frame.__init__(self, parent)

        self.choices = ("one", "two", "three", "four", "five", 
                        "six", "seven", "eight", "nine", "ten",
                        "eleven", "twelve", "thirteen", "fourteen",
                        "fifteen", "sixteen", "seventeen", "eighteen",
                        "nineteen", "twenty")

        self.entryVar = tk.StringVar()
        self.entry = tk.Entry(self, textvariable=self.entryVar)
        self.listbox = tk.Listbox(self)
        self.listbox.insert("end", *self.choices)

        self.entry.pack(side="top", fill="x")
        self.listbox.pack(side="top", fill="both", expand=True)

        self.entryVar.trace("w", self.show_choices)
        self.listbox.bind("<<ListboxSelect>>", self.on_listbox_select)

    def on_listbox_select(self, event):
        """Set the value based on the item that was clicked"""
        index = self.listbox.curselection()[0]
        data = self.listbox.get(index)
        self.entryVar.set(data)

    def show_choices(self, name1, name2, op):
        """Filter choices based on what was typed in the entry"""
        pattern = self.entryVar.get()
        choices = [x for x in self.choices if x.startswith(pattern)]
        self.listbox.delete(0, "end")
        self.listbox.insert("end", *choices)

if __name__ == "__main__":
    root = tk.Tk()
    Example(root).pack(fill="both", expand=True)
    root.mainloop()

动态tkinter输入框

1 个答案: