Question

我有一个我可能想在我的数据库中寻找的字段数组：

$locations = array(
        2,3,5
    );

位置数量可能不同，我想创建一个准备好的语句（在Symfony2中使用Doctrine），它与此相同：

SELECT * FROM locations WHERE start = 1 AND (end = 2 OR end = 3 OR end = 5)

（我认为）我知道如何使用预习语句，如下所示：

$query = $em->createQuery(
  'SELECT l
  FROM AppBundle:Location l
  WHERE l.start > :start
  AND (l.end = :end1
  OR l.end = :end2
  OR l.end = :end3)
  ORDER BY l.duration ASC'
)
->setParameter('start', '1')
->setParameter('end1', '2')
->setParameter('end2', '3')
->setParameter('end3', '5');

但是如果我没有数组的大小，我怎么能动态地做呢？

任何暗示都赞赏！

Answer 1

<?php
$locations = array(
    2,3,5
);

$query = $em->createQuery(
  'SELECT l
  FROM AppBundle:Location l
  WHERE l.start > :start
  AND l.end IN :end
  ORDER BY l.duration ASC'
)
->setParameter('start', '1');
->setParameter('end', $locations);

?>

Answer 2

@Christian的答案很好，但只是为了完成，您可以使用foreach来创建SQL字符串。

<?php
$locations = array(2, 3, 5);
$endQueries = [];

foreach ($locations as $i => $location) {
    $endQueries[] = "l.end = :end{$i}";
}

$queryString = 'SELECT l
FROM AppBundle:Location l
WHERE l.start > :start
AND (' . implode(' OR ', $endQueries) . ')
ORDER BY l.duration ASC';

$query = $em->createQuery($queryString);
$query->setParameter("start", '1');

foreach ($locations as $i => $location) {
    $query->setParameter("end{$i}", $location);
}

Answer 3

也许你错过了fetchAll？

<?php
$locations = array(
    2,3,5
);

$query = $em->createQuery(
  'SELECT l
  FROM AppBundle:Location l
  WHERE l.start > :start
  AND l.end IN :end
  ORDER BY l.duration ASC'
)
->setParameter('start', '1');
->setParameter('end', $locations);

/* == Added a fetchAll call == */
$query->execute->fetchAll();

?>

带有变量数组的Prepared Statement

3 个答案: