通过消除具有某个标志的数组对象值来查找集合中的文档

Question

考虑一个包含文档的集合（虚拟值如下所述）：

{
    id: "001",
    company: "abc",
    empDet: [
        {
            disableFlag: true,
            name: 'raj',
            age: 45,
            designation: 'clerk'
        },
        {
            disableFlag: false,
            name: 'ramya',
            age: 35,
            designation: 'manager'
        },
        {
            disableFlag: false,
            name: 'gabriel',
            age: 41,
            designation: 'asstManager'
        },
        {
            disableFlag: true,
            name: 'saran',
            age: 55,
            designation: 'attender'
        },
        {
            disableFlag: true,
            name: 'buela',
            age: 25,
            designation: 'cashier'
        }
    ],
    location: "delhi"
},
{
    id: "002",
    company: "xyz",
    empDet: [
        {
            disableFlag: true,
            name: 'ravi',
            age: 45,
            designation: 'consultant'
        },
        {
            disableFlag: true,
            name: 'reka',
            age: 35,
            designation: 'manager'
        },
        {
            disableFlag: false,
            name: 'geetha',
            age: 41,
            designation: 'asstManager'
        },
        {
            disableFlag: false,
            name: 'varun',
            age: 55,
            designation: 'attender'
        },
        {
            disableFlag: true,
            name: 'balu',
            age: 25,
            designation: 'clerk'
        }
    ],
    location: "mumbai"
},
{
    id: "003",
    company: "pqr",
    empDet: [
        {
            disableFlag: true,
            name: 'bobby',
            age: 45,
            designation: 'consultant'
        },
        {
            disableFlag: true,
            name: 'vinay',
            age: 35,
            designation: 'manager'
        },
        {
            disableFlag: true,
            name: 'faritha',
            age: 41,
            designation: 'asstManager'
        },
        {
            disableFlag: false,
            name: 'arun',
            age: 55,
            designation: 'attender'
        },
        {
            disableFlag: true,
            name: 'kayal',
            age: 25,
            designation: 'clerk'
        },
    ],
    location: "calcutta"
}

使用node.js和mongoose，我想检索xyz公司详细信息，但"empDet"的值应该只包含disableFlag的值为true。例如，我期望的输出应该是：

{
  id: "002",
  company: "xyz",
  empDet: [
    {
      disableFlag: true,
      name: 'ravi',
      age: 45,
      designation: 'consultant'
    },
    {
      disableFlag: true,
      name: 'reka',
      age: 35,
      designation: 'manager'
    },
    {
      disableFlag: true,
      name: 'balu',
      age: 25,
      designation: 'clerk'
    }    
  ],
  location: "mumbai"
}

如何通过使用node.js和mongoose消除具有某些标志为false的数组对象值来查找或检索集合中的文档？

Answer 1

在这种情况下， $redact 中的 aggregation framework 管道运营商应该适合您。这将以递归方式下降到文档结构中，并根据每个级别的指定条件的评估执行一些操作。这个概念可能有点棘手，但下面的例子证明了这一点：

Model.aggregate([
    { 
        "$match": { "company" : "xyz" }
    },
    { 
        "$redact": {
            "$cond": {
                "if": {
                    "$eq": [ "$disableFlag", false ] 
                },
                "then": "$$PRUNE",
                "else": "$$DESCEND"
            }
        }
    }
]).exec(function (err, results){
      // handle error
      console.log(results);
});

示例输出：

/* 0 */
{
    "result" : [ 
        {
            "_id" : ObjectId("562e1398bf03613b4ad1b541"),
            "id" : "002",
            "company" : "xyz",
            "empDet" : [ 
                {
                    "disableFlag" : true,
                    "name" : "ravi",
                    "age" : 45,
                    "designation" : "consultant"
                }, 
                {
                    "disableFlag" : true,
                    "name" : "reka",
                    "age" : 35,
                    "designation" : "manager"
                }, 
                {
                    "disableFlag" : true,
                    "name" : "balu",
                    "age" : 25,
                    "designation" : "clerk"
                }
            ],
            "location" : "mumbai"
        }
    ],
    "ok" : 1
}

- 更新 - 如果您想填充属于xyz公司的员工的员工详细信息，您可以使用 populate 和最新版本的mongoose，它可以在查询中递归填充相关文档。已被添加。但这需要第二个查询，并使用不同的填充方式：

var pipeline = [
    { 
        "$match": { "company" : "xyz" }
    },
    { 
        "$redact": {
            "$cond": {
                "if": {
                    "$eq": [ "$disableFlag", false ] 
                },
                "then": "$$PRUNE",
                "else": "$$DESCEND"
            }
        }
    }
];
Model.aggregate(pipeline,
    function(err, results) {
        if (err) throw err;            
        Model.populate(results, {"path": "empDet.emp_id"}, function(err, results) {
            if (err) throw err;
            console.log(JSON.stringify(results, undefined, 4));
        });
    }
);