我正在比较两天的排名。如果旧日排名>新的等级然后增加,否则减少,但我在两种情况下都减少了
SELECT
USERNAME
, SUM(IMPROVED) IMPROVED
, SUM(DECREASED) DECREASED
, SUM(NoChange) NoChange
, SUM(TimeLineCOMPLETED) TimeLineCOMPLETED
, SUM(TLNotCompleted) TLNotCompleted
FROM
(SELECT (k.keyword)
,p.projectname
,pa.username
,CASE
WHEN a.currentposition > b.currentposition
THEN 1
ELSE 0
END IMPROVED
,CASE
WHEN a.currentposition < b.currentposition
THEN 1
ELSE 0
END DECREASED
,CASE
WHEN a.currentposition = b.currentposition
THEN 1
ELSE 0
END NoChange
,CASE
WHEN pa.KeywordStatus = 'Stopped'
THEN 1
ELSE 0
END TimeLineCOMPLETED
,CASE
WHEN pa.KeywordStatus = 'InProgress'
THEN 1
ELSE 0
END TLNotCompleted
,a.currentposition AS oldposition
,b.currentposition AS newposition
,pa.KeywordStatus AS TimeLineStatus
,k.targetdate
,k.positionExp
FROM seo.tbl_keywordposition a
JOIN seo.tbl_keywordposition b ON a.keywordid = b.keywordid
AND a.psnupdatedate ='10/5/2015' AND b.psnupdatedate ='10/10/2015' LEFT JOIN tbl_keywords k ON k.keywordid = b.keywordid AND a.keywordid = b.keywordid LEFT JOIN tbl_project p ON p.ProjectId = k.ProjId LEFT JOIN tbl_projAssignment pa ON pa.ProjId = p.ProjectId AND pa.KeywordID = k.keywordid WHERE p.Projectname = 'october_project' AND a.psnupdatedate ='10/5/2015' AND b.psnupdatedate ='10/10/2015' and pa.KeywordStatus!='NULL' )INNERQUERY GROUP by USERNAME
示例数据
SELECT * FROM seo.Tbl_KeywordPosition where KeywordId in ('1514','1515')
PositionId ProjectId KeywordId CurrentPosition PsnUpdateDate
31592 129 1514 10 2015-10-05
31593 129 1514 11 2015-10-10
31594 129 1515 10 2015-10-05
31595 129 1515 9 2015-10-10
当前输出
USERNAME IMPROVED DECREASED NoChange
Ananth 0 2 0
所需的输出
USERNAME IMPROVED DECREASED NoChange
Ananth 1 1 0
因为keywordid 1514
- 旧等级10和新等级11,所以它应该减少。
keywordid 1515
- 旧等级10和新等级9,所以应该增加
答案 0 :(得分:1)
问题是CurrentPosition应该是varchar cast(a.currentpostion as int)vs cast(b.currentposition as int)
答案 1 :(得分:0)
基于样本和结果:
list
答案 2 :(得分:0)
您查询的ON子句&#34; pa.KeywordStatus!=&#39; NULL&#39;&#34;会产生不好的结果,可能你可能要把它变成pa.KeywordStatus IS NOT NULL