我正在使用JavaFX为学校开发一个简单的应用程序。我们应该制作一个白色圆圈,当按下鼠标按钮时会变为黑色,然后在释放时变回白色。对于我的生活,我无法找到我在这里出错的地方。代码编译良好,Eclipse中没有警告/错误,并给我一个空白的白色窗口。我确信这是一件很简单的事情,我长时间盯着它看错了。任何帮助深表感谢。这是代码:
import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.layout.Pane;
import javafx.stage.Stage;
import javafx.scene.shape.Circle;
import javafx.scene.paint.Color;
import javafx.scene.layout.StackPane;
public class CircleColor extends Application {
private CirclePane circlePane = new CirclePane();
@Override // Override the start method in the Application class.
public void start(Stage primaryStage) {
Pane pane = new Pane();
// Handle mouse click actions.
circlePane.setOnMousePressed(e -> {
circlePane.paintBlack();
});
// Handle mouse release actions.
circlePane.setOnMouseReleased(e -> {
circlePane.paintWhite();
});
// Create a scene & place it on the stage.
Scene scene = new Scene(pane, 200, 200);
primaryStage.setTitle("CircleColor"); // Set the stage title.
primaryStage.setScene(scene); // Place the scene on the stage.
primaryStage.show(); // Display the stage.
circlePane.requestFocus();
} // Close the start method.
// Main method only needed for IDEs with limited JavaFX support
public static void main(String[] args) {
launch(args);
} // Close the main method.
} // Close CircleColor class
class CirclePane extends StackPane {
private Circle circle = new Circle(50);
public CirclePane() {
getChildren().add(circle);
circle.setStroke(Color.BLACK);
circle.setFill(Color.WHITE);
} // Close CirclePane constructor.
public void paintBlack() {
circle.setFill(Color.BLACK);
} // Close the paintBlack method.
public void paintWhite() {
circle.setFill(Color.WHITE);
} // Close the paintWhite method.
} // Close the CirclePane class.
答案 0 :(得分:2)
您永远不会将CirclePane
添加到您的场景中。
而不是new Scene(pane,200,200);
尝试new Scene(circlePane,200,200);