Question

我有一种情况来从两个不同的表中获取数据（即fname，lname和count（jobid）），比较他们的jobid，deliverymanid，pickupmanid和employeeid来自job和employee表，并将它组合成一行。

这是工作表


jobid      pickupmanid      deliverymanid
-----   ----------------  ------------------
  1                1              2
  2                2              2
  3                1              1

这是员工表

employeeid        fname         lname
------------   -----------  -------------
    1               ABC           XYZ
    2               LMN           OPR

这就是我应该如何获得输出

employeeid   totalpickupjobs   totaldeliveryjobs       fname         lname
----------   ---------------   -----------------   -----------    -----------
    1               2               1                ABC            XYZ
    2               1               2                LMN            OPR

Answer 1

试试这个：

WITH x AS (SELECT 1 AS jobid,1 AS pickupmaid,  1 AS delivery_manid FROM dual UNION ALL
                  SELECT 2 AS jobid,2 AS pickupmaid,  2 AS delivery_manid FROM dual UNION ALL
                  SELECT 3 AS jobid,1 AS pickupmaid,  1 AS delivery_manid FROM dual ),
         y AS (SELECT 1 AS employeeid,'ABC' AS fname,  'XYZ' AS lname FROM dual UNION ALL
                   SELECT 2 AS employeeid,'LMN' AS fname,  'OPR' AS lname FROM dual )

SELECT y.employeeid as employee_id, 
        count(pickupmaid) as totalpickup, 
        count(delivery_manid) as totaldelivery, 
        y.fname as firstname, 
        y.lname as lastname
FROM y FULL OUTER JOIN x ON X.pickupmaid=y.employeeid group by y.employeeid, y.fname, y.lname;

Answer 2

试试这个：

void reverse(char *start, char *end)

转到Sql Fiddle

Answer 3

使用mysql count，inner join或group by： -

select *,count(job.deliverymanid) from Job inner 
join Pickupman on Job.pickupmanid=Pickupman.pickupmanid 
group by deliverymanid

Mysql查询我无法解决

3 个答案: