Question

这是我的代码，用于测试日期是否适用于2月份。用于测试leapYear是真还是假的顶部部分正常工作。如果我输入例如02/29/1963作为日期，则leapYear将= false。但由于某种原因，代码将继续，就像leapYear = true一样。最终结果将是：

else if (leapYear = true){
    if ((day > 0) && (day < 30) && (month ==2)){
        System.out.println("Your date is valid.)"`

它将输出“您的日期有效”。而它应该专门输出日期02/29/1963“你的日期无效，因为1963年2月只有28天。”）;

我无法弄清楚为什么会这样做。谢谢你的时间。已决议

if ((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0))) {
    leapYear = true;
} else {
    leapYear = false;
}

if (leapYear = false) {
    if ((day > 0) && (day < 29) && (month == 2)) {
        System.out.println("Your date is valid.");
    } else if (day > 29) {
        System.out.println("Your date is invalid because there are only 28 days in February"
                        + "for the year " + year + ".");
    } else {
        System.out.println("Your date is invalid because the day you entered does not exist.");
    }
} else if (leapYear = true) {
    if ((day > 0) && (day < 30) && (month == 2)) {
        System.out.println("Your date is valid.");
    } else if (day > 30) {
        System.out.println("Your date is invalid because there are only 29 days in February for"
                        + "the year " + year + ".");
    } else {
        System.out.println("Your date is invalid because the day you entered does not exist.");
    }
}

Answer 1

您的if和else-if条件不得为assignment操作而非comparison。

而不是if (leapYear = false){尝试

if (leapYear == false){

或只是

if (!leapYear){

else if (leapYear = true){相同。它将是

else if (leapYear == true){

或

else if (leapYear){

Answer 2

您无法在var looplim = 1; var infinite = 8; var k = 1; //not sure if I actually need to pass variables to function like this, although, fairly certain i am. var generator = function(infinite,looplim,k){ //value of infinite will be slowly increasing, until squared value of k is greater, and subtracted. while(infinite >= 8){ console.log("mobiasMobiasMobias"); //value of k, is retained, and incremented by 1. k = k + 1; //looplim increases, by + 8 basically, and is retained. looplim = looplim + infinite; //loopdestroyer....should be a local variable here, and does not really need to be retained since value k is being passed to it, which is retained. loopdestroyer = k*k; //new value of infinite is set and retained, the increasing value of looplim, stays above loopdestroyer, for 7 cycles, im pretty sure, unless i'm mathing wrong, looplim being 57, and loopdestroyer being 64, when the loop ends. infinite = looplim - loopdestroyer; } }; generator(infinite,looplim,k);语句中使用赋值运算符。你必须做一个平等检查：

if

Answer 3

我意识到你不能将它用于你的家庭作业，但是对于其他人而言，Java在其java.time框架中包含了这个功能。

ZonedDateTime now = ZonedDateTime.now ( ZoneId.of ( "America/Montreal" ) );
Year year = Year.from ( now );
Boolean isLeap = year.isLeap ();

转储到控制台。

System.out.println ( "year: " + year + " isLeap: " + isLeap );

跑步时。

年：2015年是飞跃：错误

Answer 4

试试这个：

if (leapYear == false) {
    if ((day > 0) && (day < 29) && (month == 2)) {
        System.out.println("Your date is valid.");
    } else if (day >= 29) {
        System.out.println("Your date is invalid because there are only 28 days in February"
                        + "for the year " + year + ".");
    } else {
        System.out.println("Your date is invalid because the day you entered does not exist.");
    }
} else if (leapYear == true) {
    if ((day > 0) && (day < 30) && (month == 2)) {
        System.out.println("Your date is valid.");
    } else if (day > 30) {
        System.out.println("Your date is invalid because there are only 29 days in February for"
                        + "the year " + year + ".");
    } else {
        System.out.println("Your date is invalid because the day you entered does not exist.");
    }
}

Java闰年逻辑错误

4 个答案: