Question

我使用模型搜索过滤并查询所有数据到控制器并将数据发送回View。查询很好，但在View中无法显示数据。而且我不知道如何解决它？

这是我的模型搜索：

$user_id = Yii::$app->user->id;

$subquery = Workload::find()->select(['p.id', 'p.project_name', 'w.user_id', 'w.commit_time', 'w.comment', 'w.workload_type'])
    ->from(['project as p', 'workload as w'])
    ->where(['and','w.user_id = '.$user_id, 'p.id = w.project_id']);

$query = Workload::find()
    ->select(['workloadTeam.project_id', 'wp.project_name', 'workloadTeam.user_id', 'workloadTeam.commit_time', 'workloadTeam.week','workloadTeam.workload_type', 'workloadTeam.comment'])
    ->from(['wp' => $subquery]);

$query->join('INNER JOIN', 'workload as workloadTeam', 'wp.id = workloadTeam.project_id')->all();

$dataProvider = new ActiveDataProvider([
     'query' => $query,
]);

在我的控制器中：

    public function actionIndex()
        {
            $searchModel = new WorkloadSearch();
            $dataProvider = $searchModel->searchWorkloadofUser(Yii::$app->request->queryParams);

            return $this->render('index', [
                'searchModel' => $searchModel,
                'dataProvider' => $dataProvider,
            ]);
        }

在我的查看索引页面中：

$gridColumns = [
    [
        'class' => 'yii\grid\SerialColumn',
        'contentOptions' => ['style' => 'width: 40px;']
    ],
    [
        'attribute' => 'user_id',
        'label' => Yii::t('app', 'Members Alias'),
        'value' => 'profile.full_name',
        'filter' => \app\modules\admin\models\User::profileDropDown(),
        'contentOptions' => ['style' => 'width: 150px;', 'class' => 'select2'],
        'filterOptions' => ['data-widget' => 'select2'],
        'format' => 'html',
    ],
    [
        'attribute' => 'project_id',
        'label' => Yii::t('app', 'Assigned Projects'),
        'value' => 'project.project_name',
        'filter' => \app\modules\admin\models\Project::projectWorkloadMemberDropdown(),
        'contentOptions' => ['style' => 'width: 150px;', 'class' => 'select2', 'placeholder' => 'Select your projects'],
        'filterOptions' => ['data-widget' => 'select2'],
        'format' => 'html',
    ],
    [
        'label' => 'Committed (hr.)',
        'value' => function ($model) {
            return $model->commit_time;
        }
    ],
    [
        'label' => 'Burned Amount (hr.)',
        'value' => function ($model) {
            return WorkLog::getTotalBurnedHoursofUser($model->user_id, $model->project_id);
        },
    ],
    [
        'attribute' => 'week',
        'filterInputOptions' => ['class' => 'form-control datepicker'],
        'value' => function ($model) {
            return $model->week;
        },
        'label' => Yii::t('app', 'From Date'),
    ],
    [
        'label' => 'Comment',
        'value' => function ($model) {
            return $model->comment;
        }
    ],
    [
        'label' => 'Workload Type',
//        'attribute' => 'workload_type',
        'filter' => \app\modules\admin\models\Workload::WorkloadTypeDropdownList(),
        'value' => function ($model) {
            return \app\modules\admin\models\Workload::$workload_type_label[$model->workload_type];
        }
    ]
];
?>

<?= GridView::widget([
        'dataProvider' => $dataProvider,
        'filterModel' => $searchModel,
        'columns' => $gridColumns,
    ]); ?>

Answer 1

我在您的代码中发现您使用的all()方法是ActiveDataProvider不需要的，因为all()方法会返回所有行，但您需要将查询对象传递给ActiveDataProvider

$user_id = Yii::$app->user->id;

$subquery = Workload::find()->select(['p.id', 'p.project_name', 'w.user_id', 'w.commit_time', 'w.comment', 'w.workload_type'])
    ->from(['project as p', 'workload as w'])
    ->where(['and','w.user_id = '.$user_id, 'p.id = w.project_id']);

$query = Workload::find()
    ->select(['workloadTeam.project_id', 'wp.project_name', 'workloadTeam.user_id', 'workloadTeam.commit_time', 'workloadTeam.week','workloadTeam.workload_type', 'workloadTeam.comment'])
    ->from(['wp' => $subquery]);

$query->join('INNER JOIN', 'workload as workloadTeam', 'wp.id = workloadTeam.project_id');

$dataProvider = new ActiveDataProvider([
     'query' => $query,
]);

之后，您可以打印$dataProvider->models以进行调试，以便从数据库获取行。如果您获得行意味着您现在可以将$dataProvider对象传递给GridView。

Yii2 Gridview没有在Index页面中显示数据

1 个答案: