将变量传递给AJAX成功

Question

这是我的代码的基本想法。我在问题中添加了评论。基本上，我需要从select（没问题）中获取值，并将其传递给AJAX查询，以便在查询（没问题）和成功（问题）中使用。

var picked_dis;
$(document).ready(function() {
$('#disease').change(function(event) {

     picked_dis = $('#disease').val();

    $.ajax({
        url: 'https://something.cartodb.com/api/v2/sql?q=SELECT territory,'+picked_dis+' from testnumbers_merge', 
//variable works in the above

        type: 'GET',
        success: function(data) {
            var ticks6 = data.rows.map(function(ele) {
                return ele.picked_dis; //this is where I want the variable to work but doesn't

            });
         console.log(picked_dis);//this returns the correct variable
            ticks6.sort(function(a, b) {
                return a - b
            });
  });
 });
 });