我一整天都在看这个,我无法弄清楚这一点。
此时加载hotel / index.html时出现错误:
NoReverseMatch at /hotel/
Reverse for 'activities' with arguments '(2,)' and keyword arguments '{}' not found. 1 pattern(s) tried: ['hotel/activities/']
Request Method: GET
Request URL: http://127.0.0.1:8000/hotel/
Django Version: 1.8.5
Exception Type: NoReverseMatch
Exception Value:
Reverse for 'activities' with arguments '(2,)' and keyword arguments '{}' not found. 1 pattern(s) tried: ['hotel/activities/']
Exception Location: /usr/local/lib/python3.4/dist-packages/django/core/urlresolvers.py in _reverse_with_prefix, line 495
Python Executable: /usr/bin/python3
Python Version: 3.4.3
Python Path:
['/home/johan/sdp/gezelligehotelletjes_com',
'/usr/lib/python3.4',
'/usr/lib/python3.4/plat-x86_64-linux-gnu',
'/usr/lib/python3.4/lib-dynload',
'/usr/local/lib/python3.4/dist-packages',
'/usr/lib/python3/dist-packages']
Server time: Sun, 25 Oct 2015 16:18:00 +0000
Error during template rendering
In template /home/johan/sdp/gezelligehotelletjes_com/hotel/templates/hotel/index.html, error at line 8
Reverse for 'activities' with arguments '(2,)' and keyword arguments '{}' not found. 1 pattern(s) tried: ['hotel/activities/']
1 {% load staticfiles %}
2
3 <link rel="stylesheet" type="text/css" href="{% static 'hotel/style.css' %}" />
4
5 {% if netherlands_city_list %}
6 <ul>
7 {% for city in netherlands_city_list %}
8
<li><a href="
{% url 'hotel:activities' city.id %}
">{{ city.name }}</a></ul>
9 {% endfor %}
10 </ul>
11 {% else %}
12 <p>No polls are available.</p>
13 {% endif %}
以下是我认为与此错误相关的代码。
网站/ urls.py
from django.conf.urls import include, url
from django.contrib import admin
import hotel.views
urlpatterns = [
url(r'^hotel/', include('hotel.urls', namespace='hotel')),
url(r'^admin/', include(admin.site.urls)),
]
酒店/ urls.py
from django.conf.urls import include, url
from django.contrib import admin
from hotel import views
urlpatterns = [
url(r'^$', views.IndexView.as_view(), name='index'),
url(r'^activities/$', views.ActivitiesView.as_view(), name='activities'),
]
酒店/ index.html中
{% load staticfiles %}
<link rel="stylesheet" type="text/css" href="{% static 'hotel/style.css' %}" />
{% if netherlands_city_list %}
<ul>
{% for city in netherlands_city_list %}
<li><a href="{% url 'hotel:activities' city.id %}">{{ city.name }}</a></ul>
{% endfor %}
</ul>
{% else %}
<p>No cities are available.</p>
{% endif %}
酒店/ activities.html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title></title>
</head>
<body>
</body>
</html>
和hotel / views.py
from django.shortcuts import render
from django.views import generic
from django.core.urlresolvers import reverse
from .models import Hotel
from base.models import City
class IndexView(generic.ListView):
template_name = "hotel/index.html"
context_object_name = "netherlands_city_list"
def get_queryset(self):
return City.objects.filter(state__country__name__exact="Netherlands").order_by('name')[:5]
class ActivitiesView(generic.ListView):
template_name = "hotel/activities.html"
我现在整天都在四处寻找,但无法弄清楚这一点。 (虽然它可能是那些较小的东西之一。)
我希望有人可以帮助解决这个问题。
提前致谢。
答案 0 :(得分:3)
您的问题出在您的网址中:
url(r'^activities/$', views.ActivitiesView.as_view(), name='activities'),
您的模板调用参数活动:
<a href="{% url 'hotel:activities' city.id %}">
但是这个论点并没有作为参数传递。解决方案是:
url(r'^activities/(?P<city>[0-9]+)/$', views.ActivitiesView.as_view(), name='activities'),
答案 1 :(得分:2)
在模板中,您尝试与位置参数(城市ID)进行反向匹配
{% url 'hotel:activities' city.id %}
但是,在您的urlpatterns中,您尚未在网址定义中设置任何参数规则
url(r'^activities/$', views.ActivitiesView.as_view(), name='activities'),
所以,你有这个错误
Reverse for 'activities' with arguments '(2,)' ... not found.
检查文档以完成您的目标。
https://docs.djangoproject.com/en/1.8/topics/http/urls/
您可能需要添加城市ID与您的网址匹配的正则表达式组
url(r'^activities/([0-9]+)/$', views.ActivitiesView.as_view(), name='activities'),
(后者只是一个想法,你需要根据你的情况修改它)。