我创建了一个<div class="post-main-area">
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</div>表。当我尝试填充它时，我得到time_zones说我需要包含TypeError值。
postgresql中的表：
id来自\d+ time_zones
Table "public.time_zones"
Column | Type | Modifiers | Storage | Stats target | Description
------------+-----------------------------+---------------------------------------------------------+----------+--------------+-------------
id | integer | not null default nextval('time_zones_id_seq'::regclass) | plain | |
name | character varying(128) | not null | extended | |
created_at | timestamp without time zone | | plain | |
updated_at | timestamp without time zone | | plain | |
Indexes:
"time_zones_pkey" PRIMARY KEY, btree (id)
"time_zones_name_key" UNIQUE CONSTRAINT, btree (name)
Referenced by:
TABLE "app_users" CONSTRAINT "app_users_time_zone_id_fkey" FOREIGN KEY (time_zone_id) REFERENCES time_zones(id)
的TimeZone类：
models.py class TimeZone(db.Model):
__table_name__ = 'time_zones'
id = db.Column(db.Integer, db.Sequence('time_zones_id_seq'), primary_key=True, nullable=False)
name = db.Column(db.String(128), nullable=False)
created_at = db.Column(db.TIMESTAMP(timezone=False), default=_get_date)
updated_at = db.Column(db.TIMESTAMP(timezone=False), onupdate=_get_date)
迁移文件：
Alembic我尝试通过带有def upgrade():
op.create_table('time_zones',
sa.Column('id', sa.Integer, primary_key=True, nullable=False),
sa.Column('name', sa.String(128), nullable=False, unique=True),
sa.Column('created_at', sa.TIMESTAMP(timezone=False), default=_get_date),
sa.Column('updated_at', sa.TIMESTAMP(timezone=False), onupdate=_get_date))
的烧瓶外壳向time_zones表添加名称：
TypeError如果我在>>> from app.main.models import TimeZone
>>> from app import db
>>>
>>> tz = TimeZone(name='Central Time (US & Canada)')
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "<string>", line 2, in __init__
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/orm/instrumentation.py", line 347, in _new_state_if_none
state = self._state_constructor(instance, self)
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/util/langhelpers.py", line 747, in __get__
obj.__dict__[self.__name__] = result = self.fget(obj)
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/orm/instrumentation.py", line 177, in _state_constructor
self.dispatch.first_init(self, self.class_)
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/event/attr.py", line 256, in __call__
fn(*args, **kw)
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/orm/mapper.py", line 2860, in _event_on_first_init
configure_mappers()
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/orm/mapper.py", line 2756, in configure_mappers
mapper._post_configure_properties()
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/orm/mapper.py", line 1710, in _post_configure_properties
prop.init()
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/orm/interfaces.py", line 183, in init
self.do_init()
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/orm/relationships.py", line 1612, in do_init
self._process_dependent_arguments()
File "/usr/local/lib/python3.4/dist-packages/sqlalchemy/orm/relationships.py", line 1637, in _process_dependent_arguments
setattr(self, attr, attr_value())
TypeError: id() takes exactly one argument (0 given)
中删除了我的AppUser类中的关系，我不会再出现此错误。所以我不能正确设置我的关系。
以下是app.auth.models models.py模块：
auth答案 0 :(得分：2)
我刚刚在自己的代码中解决了类似的问题，问题出在{“1}}上，定义了您在”UPDATE“中注释掉的关系。当您以这种方式声明排序时，SQLAlchemy会尝试使用AppUser的order_by=id属性进行排序，因为声明在AppUser类中。由于AppUser没有列或其他名为'id'的属性，因此python访问内置的id（）方法，不能在没有参数的情况下使用（并且无论如何都不能用于排序关系）。
我敢打赌，将order_by参数更改为id或order_by=TimeZone.id可以清除错误;类似的更改修复了我的代码中的问题。