Question

我正在尝试使用以下php代码从xampp服务器发送电子邮件。 Php代码似乎工作正常，因为它提供了所有成功和错误消息，但我没有收到我在表单中提供的电子邮件的任何邮件。

<!-- Core plugins -->
<gap:plugin name="org.apache.cordova.battery-status" />
<gap:plugin name="org.apache.cordova.camera" />
<gap:plugin name="org.apache.cordova.media-capture" />
<gap:plugin name="org.apache.cordova.console" />
<gap:plugin name="org.apache.cordova.contacts" />
<gap:plugin name="org.apache.cordova.device" />
<gap:plugin name="org.apache.cordova.device-motion" />
<gap:plugin name="org.apache.cordova.device-orientation" />
<gap:plugin name="org.apache.cordova.dialogs" />
<gap:plugin name="org.apache.cordova.file" />
<gap:plugin name="org.apache.cordova.file-transfer" />
<gap:plugin name="org.apache.cordova.geolocation" />
<gap:plugin name="org.apache.cordova.globalization" />
<gap:plugin name="org.apache.cordova.inappbrowser" />
<gap:plugin name="org.apache.cordova.media" />
<gap:plugin name="org.apache.cordova.network-information" />
<gap:plugin name="org.apache.cordova.splashscreen" />
<gap:plugin name="org.apache.cordova.vibration" />

我还对<?php if(isset($_POST['submit'])){ $email = $_POST['email']; if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {// Validate email address $message = "Invalid email address please type a valid email!"; } else { $query = $con->prepare("SELECT username FROM members where email=:email"); $query->execute(array(':email'=>$email)); $row = $query->fetch(PDO::FETCH_ASSOC); if($query->rowCount() == 1) { $encrypt = md5(1290*3+$row['username']); $message = "Your password reset link has been send to your e-mail address. Check your mail and click on the link therein."; $to=$email; $subject="Password Recovery"; $from = 'mydemo.com'; $body='Hi, <br/> <br/>Your username is '.$row['username'].' <br><br>Click here to reset your password http://localhost/mydemo/reset.php?encrypt='.$encrypt.' <br/> <br/>--<br>'; $headers = "From: " . strip_tags($from) . "\r\n"; $headers .= "Reply-To: ". strip_tags($from) . "\r\n"; $headers .= "MIME-Version: 1.0\r\n"; $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n"; mail($to,$subject,$body,$headers); } else { $message = "Account not found please enter email you provided during sign up!"; } } } <form action="" method="POST"> <legend>Forgot your password!</legend> <input type="email" name="email" id="email" required="required" maxlength="35" placeholder="Enter your email here..."/> <input type="submit" name="submit" id="submit" value="Submit"/> </form> <div id="message"><?php echo $message; ?></div>和C:\xampp\php\php.ini进行了以下更改，实际上我有两个php.ini开发和生产。我对c:\xampp\sendmail\sendmail.ini

进行了更改

php-ini-development

Answer 1

if (!mail($to,$subject,$body,$headers)) {
   /*Here you can log error*/
   print_r(error_get_last());
}

Answer 2

您不知道它是否正常工作，因为您没有检查函数mail（）的结果。如果

，请添加一个

if (false === mail($to,$subject,$body,$headers)) {
   $message = "Mail was not sent";
}

来自手册：

如果邮件成功接受传递，则返回TRUE，否则返回FALSE。

重要的是要注意，仅仅因为邮件已被接受发送，并不意味着邮件实际上会到达目的地。

通过mail（）函数从本地服务器发送电子邮件

2 个答案: