Question

我遇到了Django和Python的问题

我遇到错误.from_hour: (fields.E005) 'choices' must be an iterable containing (actual value, human readable name) tuples.有人可以帮我理解错误是什么吗？我知道如果我评论from_hour和to_hour它会运行

这是我的代码

WEEKDAYS = [
  (1, _("Monday")),
  (2, _("Tuesday")),
  (3, _("Wednesday")),
  (4, _("Thursday")),
  (5, _("Friday")),
  (6, _("Saturday")),
  (7, _("Sunday")),
]


weekday_from = models.IntegerField(choices=WEEKDAYS, unique=True)
weekday_to = models.IntegerField(choices=WEEKDAYS)
from_hour = models.IntegerField(choices=range(1,25))
to_hour = models.IntegerField(choices=range(1,25))

def get_weekday_from_display(self):
    return WEEKDAYS[self.weekday_from]

def get_weekday_to_display(self):
    return WEEKDAYS[self.weekday_to]

Answer 1

错误与from_hour有关。您应该提供像from_hour = models.IntegerField(choices=[(x, str(x)) for x in range(1,25)])这样的元组集合。我认为你应该对to_hour字段做同样的事情。

Answer 2

您必须在＆＃39;＆＃39;

中设置值

STATUS_CHOICES = (
    ('d', 'Draft'),
    ('p', 'Published'),
)

Answer 3

您必须在选择属性中使用 WEEKDAYS.choices ，更改此行：

weekday_from = models.IntegerField(choices=WEEKDAYS, unique=True)

到

weekday_from = models.IntegerField(choices=WEEKDAYS.choices, unique=True)

选择必须是可迭代的

3 个答案: